Hello,
I'm starting in Assembly development. Then recently i buy a book of Assembly, in it i have the table with the decimal numbers to hexamals and to binarys, like this:

Dec - Hex
1 - 01
2 - 02
3 - 03
4 - 04
[...]
10 - A
11 - B
12 - C
13 - D
14 - E
15 - F

And at thee appendix of the book i have the conversions of all the numbers and ASCII to hexamal and to binary, but i want to know what is the calc to convert decimal numbers in hexamal, like 63 = 3F , what is the calc that i have to do to tranform 63 in hexamal that is 3F, this is just to learn more.

Thanks,
Nathan Paulino Campos

All values stored in memory are represented in binary,
so I would assume that if you had a decimal value
it would be the ASCII representation of a decimal value,
as if it were entered in by the keyboard.
So the value 63 would be represented thus in ASCII:
36h='6' 33h='3'
All you would need to do is turn that ASCII representation
into a value in memory, then convert that to hexadecimal.
So 63=6*10+3*1, thats how you do it.
To turn a value in memory into the ASCII representation
of a hexadecimal value, bitshifting is employed:

mov al,63
mov bl,al
shr al,4
xor ah,ah
mov si,ax
mov dl,[hexdig+si]
call print
mov al,bl
shl al,4
shr al,4
xor ah,ah
mov si,ax
mov dl,[hexdig+si]
call print
int 20h
print:
mov ah,02
int 21h
ret
hexdig db '0123456789ABCDEF'

H = 15 , why the h after all the numbers that you have entered in the beginning of your answer?
Why 36 and 33?

Thanks!

Now i know, like 42, in hexamal it will be 2A and the calc is this: 42 = 16 * 2 + 10 , because 42 was divided by 16 with the quotient 2 and the remainder is 10, the it will be 2A.
Thanks for Jester01 in the ##asm channel of FreeNode that helped me with this!

This question has already been answered. Start a new discussion instead.