L = [ 0 , 2, 1 , -1 , -1 , -1, -1 ]
for i in L:
if i <= 0:
L.pop ( i )
print LWhat I was expecting was that L = [ 0, 2, 1 ]
but the result was [ 2 , 1 , -1, -1 ]
I would like to know why it is such.
( I would also like to directly post python code over here, but I don't know how? )
Jump to PostWhat I was expecting was that L = [ 0, 2, 1 ]
but the result was [ 2 , 1 , -1, -1 ]I would like to know why it is such.
You're using the pop() method of a list. It pop's a value from a list at …
What I was expecting was that L = [ 0, 2, 1 ]
but the result was [ 2 , 1 , -1, -1 ]I would like to know why it is such.
You're using the pop() method of a list. It pop's a value from a list at INDEX x, not a VALUE x. So when you say that if i is smaller then 0: pop i You're removing the item at INDEX i. So when i == -1, python will try to pop at INDEX -1, which doesn't exist.
( I would also like to directly post python code over here, but I don't know how? )
Post your code like this:
[code]
... code here
[/code]
If you'd read the rules, you would have known this.
What I was expecting was that L = [ 0, 2, 1 ]
If you what this result is better to iterate over the list and append the result to a new list.
L = [ 0 , 2, 1 , -1 , -1 , -1, -1 ]
new_list = []
for item in L:
if item >= 0:
new_list.append(item)
print new_list
''' my output-->
[0, 2, 1]
'''
#Or more fancyer with list comprehension
lst = [item for item in L if item >= 0]
print lst
''' my output-->
[0, 2, 1]
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