Hello all,

I would be grateful for your advice regarding something I tried to do using unique() but it didn't work.

I have a two dimensional numpy array that looks like that (but much larger):

>>> pop_A1

array([[10, 2, 10],

[10, 9, 10],

[10, 9, 10],

[10, 9, 10],

[10, 9, 10],

[22, 9, 10],

[10, 9, 10],

[10, 9, 10],

[10, 9, 10],

[10, 9, 10]])

From that I need to create a unique list (or array), specifying unique vectors and how many of each of them are there. So for example, I have here 3 unique vectors which are [10, 2, 10], [10, 9, 10] and [22, 9, 10]. The first vector appears one time, the second appears 8 times, and the third appear one time, so I would like my output be something like:

[10, 2, 10] 1

[10, 9, 10] 8

[22, 9, 10] 1

When I use unique() it seems to "flatten" the two dimensional array, and I only get:array([ 2, 9, 10, 22]).

Many thanks for any suggestion!