I'm trying to copy a variable from a vector into an array (with a few steps in between)
As you can see from the code, I take a random piece of equipment from the vector of equipments and insert it into the inventory (which is an array).
The line marked with the <---- gives a warning in the compiler.
warning: taking address of temporary

// Static list of monsters & equipment
vector<CMonster> monsters;
vector<CEquipment> equipments;
vector<CPotion> potions;
vector<CBag> bags;

template <typename T>
void load_from_file(vector<T> & v, const char * filename) {
	ifstream in(filename);
	if (!in.is_open())
		throw runtime_error(string("File does not exist: ") + filename);

	string line;
	while (getline(in, line)){
		if (line[0] == 'P'){
		else if (line[0] == 'Z'){

template <typename T>
T random_from(const vector<T> & v) {
	return v[d(1, v.size()) - 1];

void Battle(CPlayer player, int count){

// code omitted

	if (count > 1 and player.Alive()){
	// generate an amount of gold
		int amt = rand()%100;
		cout << "You get " << amt << " gold from the " << monster.GetName() << endl;
	// less money is compensated with a weapon
	//if (amt < 20){
		CEquipment* equipment = &(random_from<CEquipment>(equipments)); //<-----
		cout << "You search the room and find: " << *equipment << "."<< endl;
		cout << "What do you do? (e)quip, (c)ontinue, add to (i)nventory " << endl;
		cin >> move;
		switch (move){
			case 'e': 
			case 'i':

	else {cout << "You survived the dungeon!" << endl << "Your final stats: " << player << endl;}

// code omitted


When I print out the inventory after one addition, its correct but after the second addition it says that both elements are the same and equal to the last added item.

How can I resolve this issue? I know the inventory works as it should, the display function is also correct.
I thinks its something with the fact that the equipment from the vector is given through a few functions. But I don't see the solution.



>>CEquipment* equipment = &(random_from<CEquipment>(equipments));

This is what you are doing :

int * pointer = 0; //declared somewhere
void foo(){
  int a = 3;
   pointer= &a; //what you are doing
}//end of the brackets

now at the end of the brackets, a gets destroyed, and what does
pointer points too?

Edited 6 Years Ago by firstPerson: n/a

In the meanwhile I've solved it. I needed to use the new-keyword when creating the equipments.

But thanks anyway.

In the meanwhile I've solved it. I needed to use the new-keyword when creating the equipments.

But thanks anyway.

Make sure you match a delete with that!

That's what I was trying to figuring out. Where should I put the delete?
The elements are in a vector of pointers to them. It stays static for the whole run of the program.
Do I have to put the deletes right before the program exits?

You have to delete it at a point where you can guarantee that after the delete you won't access it anymore.
This can be at the end of an application, in the destructor of a class or just somewhere in a function that prints the variable and is then done with it.

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