I'm getting three different values for EOF

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0

printf ("%d",EOF);

This gives me -1

scanf ("%d",&a);

printf ("%d",a)

where a is int (as EOF is an int), this gives me some junk value

printf ("%d",getch());

This gives me 26

I've always given the input as ctrl+z (that's right, na!)

What's the correct value of EOF ?

c

Edited 8 Years Ago by WaltP: Use the PREVIEW button so you can correct badly formatted posts

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Last Post by Narue

This Question has been Answered

c

gerard4143 371 · Answer 1 · 2009-12-31T01:58:41+00:00

I hope this link will straighten you out:

http://en.wikipedia.org/wiki/End-of-file

Narue 5,707 · Answer 2 · 2009-12-31T03:14:02+00:00

EOF isn't a character from the stream.

daudiam -8 · Answer 3 · 2010-01-01T00:52:49+00:00

Thanks !

Plz take time out to check if I have understood correctly

EOF is a value returned when the end of an input stream occurs. Its value in most systems is -1. In C, EOF is a macro defined as -1. Note that EOF is not some character returned from the input stream. In Unix, the end of input is indicated by ctrl+d (whose ascii value is 4) while in Windows, its Ctrl+Z (whose ascii value is 26). When receiving an input stream, if Ctrl+Z is sensed in Windows or Ctrl+D in Windows, Its interpreted as the end of input, and EOF (i.e. -1) is returned to the program. Both of them are also called EOT (End of transmission

character for their respective environments).

Narue 5,707 · Answer 4 · 2010-01-01T01:20:47+00:00

>Its value in most systems is -1.
The actual value is irrelevant.

>In C, EOF is a macro defined as -1.
EOF is defined as a negative constant with a type of int, nothing more.