An unsigned long(9999999000) returns 1410064408.
Any explanation to it?
GyanPP
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Jump to PostWhat do you mean "returns" ?
Jump to Post>To specify a 64-bit integral (long long) type, use the LL or ll suffix.
However, note thatlong longis not standard C++ yet (C++0x is nearing completion though), so you might encounter either complete failure or a difference in the details with various compilers.
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Nick Evan
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What do you mean "returns" ?
GyanPP
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Newbie Poster
What do you mean "returns" ?
returns in the sense the value returned when the number 9999999000 is typecasted into unsigned long is 1410064408.
I wanted to know why this happens.
Nick Evan
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a 32-bits unsigned long can hold a number no larger then 2^32 = 4294967296, so it'll overflow and become zero again.
So if you do 9999999000 % (mod) 4294967296 = 1410064408
kvprajapati
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To specify a 64-bit integral (long long) type, use the LL or ll suffix.
..
std::cout << 9999999000LL;
..
Narue
5,707
Bad Cop
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>To specify a 64-bit integral (long long) type, use the LL or ll suffix.
However, note that long long is not standard C++ yet (C++0x is nearing completion though), so you might encounter either complete failure or a difference in the details with various compilers.
kvprajapati
commented:
Agree!
+6
GyanPP
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Newbie Poster
Great! thanks a lot!
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