I'm working with Kochan's Programming in C. I am working in Visual Studio 2008. When I try to build the program I get

Error 2 error C2143: syntax error : missing ';' before 'type' c:\users\michael\documents\visual studio 2008\projects\cpractice\cpractice\char.c 15 CPractice

But as far as I'm aware there is no syntax error. It seems the issue is declaring the array after the printf and scanf functions have been called. If I put

unsigned long long int Fibonacci[5];

before the function calls, it works fine. Put it after, error.


int main (void)
	int i, numFibs;

	printf("How many Fibonacci numbers do you want (between 1 and 75)? ");
	scanf("%i", &numFibs);

	if (numFibs < 1 || numFibs > 75) {
		printf("Bad number, sorry!\n");
		return 1;
	unsigned long long int Fibonacci[numFibs];

	Fibonacci[0] = 0;
	Fibonacci[1] = 1;

	for (i=2; i<numFibs; ++i)
		Fibonacci[i] = Fibonacci[i-2] + Fibonacci[i-1];

	for (i=0; i<numFibs; ++i)
		printf("%llu ", Fibonacci[i]);


	return 0;

> before the function calls, it works fine. Put it after, error.
That's because your C doesn't allow mixing declarations and statements.

It's allowed in C99, but you don't have a C99 compiler.

You will have to use malloc.

Try using my code:

#include <stdio.h>

int main()
unsigned int n;
int k, l;
int p = 0;
k = 1;
l = 0;
scanf("%d", &n);
while((k<=n) && (l<=n))
  if(p % 2 == 0)
  l = k + l;
    if(l <= n)
    printf("%d\n", l);
  k = k + l;
    if (k <= n)
    printf("%d\n", k);

n is the same as your numFib


Because at first we can declare something like:
int *a;

and then


then we wont require value of 'n' prior to the array declaration.

Why not just int a[100]; Or, knowing the limitation of int just declare the array as int a[41]; and save the time and processing to input a value and call malloc() ?

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