I am trying to count the characters in a linked list.
I am receiving a compiler error when this function is tested...
**invalid types `char[int]' for array subscript **
int slist::count_c(char c) const
{
slistelem* temp = h;
int count = 0;
for (int i = 0; i != '\0'; i++)
if (temp == c[i])
count ++;
return count;
}How can I fix this function to properly display desired results?
With a function call such as
cout << l.count_c('b') << endl;Jump to Post>> if (temp == c)
Your compiler is correct. Variable c is a single character, not a character array. Maybe you mean
if (temp[i] == c)
Jump to Post>>i != '\0'
BAD idea!
>> if (temp == c)
Your compiler is correct. Variable c is a single character, not a character array. Maybe you mean if (temp[i] == c)
if( c == temp)
is incorrect as well and gives me this error message:
no match for 'operator==' in '*((+(((unsigned int)(i++)) * 8u)) + temp) == c'
how else can i compare a character to the indexing array?
>>i != '\0'
BAD idea!
how is slistelem declared?
struct slistelem
{
char data;
slistelem* next;
};Since its a linked list you can not access the nodes in the for loop that you posted, but since you already marked this thread solved I suppose you already figured that out.
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.