Write a Python program that creates a dictionary of son-father pairs-you can make the pairs with fictional names for fun. Your program should populate this dictionary with the son-father pairs
you made up.

Your program should present the user a menu with two options. The following is an example:

Father Finder
0 - Quit
1 - Find a Father

A user input of 0 should end the program. A user input of 1 should cause the program to prompt
the user for the name of a son. If the dictionary contains the son-father pair, the program should
display the father. Otherwise, the program should tell the user it does not know.


My program code below, I got this, entering 0 works, but entering a run just repeats the enter a number choice option, anyone help me out to make it enter a name when entering 1?
-----------------------------------------------------------------------------------------

pairs = {"Jeremy": "Jerome",
"Jason": "Fred",
"Joe" : "Fred",
"Alayna" : "Tom",
"Jay" : "Jerome",
"April" : "Tom"}


choice = None

while choice != "0":

choice = raw_input(
"Please Enter a Number Choice: ")

# Finish

if choice == "0":

print "I guess you are done."

# get a definition

elif choice == "1":
choice = raw_input("Please enter a Name: ")

print "\n This is your current list \n\n", pairs


else:

print "\nI can't do that!", pair, "doesn't exist in the dictionary."

print\
"""

Father Finder


0 - Quit

1 - Find a Father

"""

Use code tag next time,not quote tags.
Look at this code ande try to write the rest(if-else)

pairs =\
{"Jeremy": "Jerome",
 "Jason": "Fred",
 "Joe" : "Fred",
 "Alayna" : "Tom",
 "Jay" : "Jerome",
 "April" : "Tom"}


def find_father():    
    print "\n This is your current list \n\n", pairs.keys() #We print only sons names
    pass      

def main():
    '''Main menu and info ''' 
    while True:               
        print 'Father finder'
        print '(1) 1 - Find a Father'        
        print '(q) Quit' 
        choice = raw_input('Enter your choice: ') 
        if choice == '1':
            find_father()       
        elif choice == 'q': 
            return
        else: 
            print 'Not a correct choice:', choice 

if __name__ == '__main__':
    main()

Hint.

>>> choice_name = 'Jay'
>>> if choice_name in pairs:
...     print 'Father name is %s' % pairs[choice_name]
...     
Father name is Jerome
>>>

Ok here you go,read a little more about dictionary an basic stuff;)

pairs =\
{"Jeremy": "Jerome",
 "Jason": "Fred",
 "Joe" : "Fred",
 "Alayna" : "Tom",
 "Jay" : "Jerome",
 "April" : "Tom"}

def find_father():    
    print "\n This is your current list \n\n", pairs.keys() #We print only sons name 
    choice_name = raw_input("Please enter a Name: ")
    if choice_name in pairs:
        print 'Father of %s is %s ' % (choice_name, pairs[choice_name])        
    else:
        print 'Name not in database'
    raw_input("\nTrykk enter for meny\n")   

def main():
    '''Main menu and info ''' 
    while True:               
        print 'Father finder'
        print '(1) Find a Father'        
        print '(q) Quit' 
        choice = raw_input('Enter your choice: ') 
        if choice == '1':
            find_father()       
        elif choice == 'q': 
            return
        else: 
            print 'Not a correct choice:', choice 

if __name__ == '__main__':
    main()

Edited 6 Years Ago by snippsat: n/a

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