How to delete a non dynamic variable?

[merse]

Is it possible to delete a non dynamic variable?
Or is it automatically deleted when I construct a new one with the same name?

int N;
int N;

Is this possible?

My purpose is, that I want to use an object from a class in a loop:

for(;;)
{
  myobj = myclass(param1,param2);
}

but the class hasnt got an empty constructor: myclass();
Therefore I cannot write:

mycass myobj;
for(;;)
{
  myobj = myclass(param1,param2);
}

[thomas_naveen]

Can you use the following?

myclass *myobjptr;
for(;;)
{
  myobjptr = new myclass(param1,param2);


  //Code

   delete myobjptr;
}

This is not really a good way of doing things as it might result in heap fragmentation due to the frequent allocation and deletes of memory involved.

[Banfa]

In a loop like this

int main()
{
    for(int ix = 0; ix<5; ix++)
    {
        MyObject obj = MyObject(ix);
    }
}

obj is constructed and destricted on every loop iteration. Put cout statements in the constructor and destructor if you wish to confirm it.

[n.utiu]

Any non-dynamic variable is deleted at the end of it's scope.

mycass myobj;
for(;;)
{
  myobj = [B]myclass(param1,param2);[/B]
}

The bolded object is deleted just before the compiler reaches the next line. It's scope spans just until the end of that assignment.

[mrnutty]

Just for emphasis, an automatic variable is deleted with it reaches
the end of its block. So for example :

int main(){
  {
      int x = 0;
   } //x is deleted when it reaches this bracket
  
    int x = 3, y = 3
} //x and y is deleted when it reaches this bracket

so as you see, you can use "{ ... }" the bracket to destroy the variable.
But you should try to give each variable unique name and not have to
do that.