Factoring an Array

[bbrradd]

my code will read in a file and put the integers in the file into the array. It reads in and displays the integers perfectly, but i am stuck on how to find the factors of each number in the array. when i use my code i get the error: invalid operands to binary.

example:

4, factors = 3
6, factors = 4

#include <iostream>
#include <cmath>
#include <fstream>
#include <iomanip>
using namespace std;
const int MAX = 30;
void getfilename(string,string&);
void get_data(ifstream&, double[], int&);
double factor(double[], int);
int main()
{
  int n;
  double fac;
  double list[MAX];
  ifstream input;
  string filename, file;
  getfilename("input",filename);
  input.open(filename.c_str());
  get_data(input,list,n);
  input.close();
  fac = factor(list, n);
  for (int j=0; j<n; j++)
    {
      cout << list[j] << right << setw(16) << fac << endl;
    }

  return 0;
}

double factor(double data[], int n)
{
  int facts = 2;
   for (int j=0; j<n; j++)
 {
   if (list[j]%2 == 0)
     facts++;
   }
 return facts;
}
void getfilename(string filetype,string& filename)
{
  cout << "Enter name of " << filetype << " file\n";
  cin >> filename;
}
void get_data(ifstream& input,double list[],int& n)
{
  n=0;
  int count = 0;
  input >> list[n];
  while (!input.eof())
    {
      n++;
      count++;
      input >> list[n];
    }


}

[StuXYZ]

There are a few little errors:
(a) You have tried to write a factor that somehow works on the whole array.
(b) You have forgotten that if you get clever and add two factors because any number N, has factors 1 and N. Not to test them
(c) why does factor return a double?

double factor(double data[], int n)   // this should take a number N
{
int facts = 2;
for (int j=0; j<n; j++)        // THIS loop should be j=2;j<N;j++
{
  if (list[j]%2 == 0)   // THIS is wrong 
  facts++;
}
return facts;
}

Please turn on your compiler warnings and never ignore them.