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How do I use the OpenFileDialog class (in C#, WPF etc.) such that it opens on the Network area as default?

This does not work:

OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "Network";

I also tried having "\\" as an InitialDirectory and that did not work.

I also tried having "\\\\" as an InitialDirectory and that did not work either.

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  • Latest Post Latest Post by nick.crane
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Try this

openFileDialog1.InitialDirectory = "::{208D2C60-3AEA-1069-A2D7-08002B30309D}";

Edited by nick.crane because: n/a
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