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I am going some exercises and just want to make sure I am doing it right. It says for the following...Assume StackType is sent to int and STACK_CAPACITY is set to 5. Give the values of myTop and the contents of the array referred to by myArray in the stack s after the code segment is executed or indictate why an error occurs.

Stack s;
s.push(10);
s.push(22);
s.push(37);
s.pop();
s.pop();

I am guessing the answer is 10[6] and this is how I figured it in case I am doing it wrong. I starts with s at 5 and each push increases by one and each pop decreases by 1. Please let me know if this is not how I am supposed to do this question.

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Last Post by chiwawa10
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We do not know what myTop or myArray are supposed to represent.
However, it's safe to say that at the end the top (and only) element is 10, the stack size is 1 and the capacity probably will be still 5.

Edited by Aranarth: n/a

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I did some additional reading and I think 5 is the total it can be so correct me if I am wrong but shouldnt it start with 0,1,2,3,4 with 0 at s, 1 at 10, etc

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I figured out the last questions but I do have a question with the next one....

Here is my next question...

Stack s;
s.push(10);
s.push(9);
s.push(8);
while(!s.empty())
s.pop();

and the while (!s.empty() equation is myTop < Stack_CAPACITY - 1 so 2 < 4 so this statement can be ignored correct?

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You need to express yourself more clearly. You have still not explained what myTop is supposed to be.
If you want to know what while(!s.empty())s.pop(); does: it removes all elements from the stack.

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I apologize I am jus trying to understand these topics so just a little difficult to explain when I am not as familiar with the material but ill try harder

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I think I have these done but not sure if they are right. As far as myTop goes I dont think I was ever given it...

1.

Stack s;

s.push(10);

s.push(22);

s.push(37);

s.pop();

s.pop();

This answer I put 10[0]

2.

Stack s;

s.push(10);

s.push(9);

s.push(8);

while(!s.empty())

s.pop();

This answer I put cannot be done because the last statement clears everything out

3.

Stack s;

for (int i = 1; i <= 6; i++)

s.push(10*i);

Cannot be done because I is multiplied by 10 and the
highest it can be is 6

4.

Stack s;

s.push(11);

i = s.top();

s.pop();

This answer I put
3[0]

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