I am trying to solve the problem Present at http://www.codechef.com/problems/INTEST/

I have made a small Python script to do my job :-

array = []
no_lines = 0
no = 0 
j=0 
div_no=0
no_lines = input()
no = input()
temp = no_lines 
while(no_lines>0) :
	i=0 
	i = input()
	array[j] = i
	j = j+1
	no_lines = no_lines - 1
j=0

while(j<temp) :
	if array[j] % no == 0 :
		div_no=div_no+1 
	j = j+1

print(div_no,"\n")

I am having a problem in Inputing 2 integers on the same line

no_lines = input()
no = input()

I am really confused...How to get a successful output:-

In case of the following input:-

7 3
1
51
966369
7
9
999996
11

Error:-

SyntaxError: unexpected EOF while parsing

With python 2, don't use input, use raw_input, which returns a string, and convert the result to an int. Here is a modified version which runs (but you didn't choose the fastest way to solve the problem :) )

import sys
if sys.version_info < (3,):
    input = raw_input
    
array = []
no_lines = 0
no = 0 
j=0 
div_no=0
no_lines, no = [int(x) for x in input().split()]
temp = no_lines 
while(no_lines>0) :
	i=0 
	i = int(input())
	array.append(i)
	no_lines = no_lines - 1
j=0

while(j<temp) :
	if array[j] % no == 0 :
		div_no=div_no+1 
	j = j+1

print(div_no,"\n")

Edited 6 Years Ago by Gribouillis: n/a

Input the two numbers as a string
split the string into a two item list
check if each item is a valid number
then use the index to get at each numeric item
convert each number with float()

Here is a little function to check if a string is numeric ...

def isnumeric(s):
    """test if a string s is numeric"""
    for c in s:
        if c not in "1234567890-+.":
            return False
    return True

Edited 6 Years Ago by vegaseat: n/a

I did my number checking routine before but simplest is best for me now:

def isnumeric(s):
    try:
       s=float(s)
       return True
    except ValueError: 
       return False

for text in ('one',3242,'342.342','1e6'):
     print text,isnumeric(text)

Or even:

def tofloat(s):
    try:
       s=float(s)
       return s
    except ValueError: 
       return None

def isnumeric(s):
    return tofloat(s) is not None

for text in ('one',3242,'342.342','1e6'):
     print text,tofloat(text)

Edited 6 Years Ago by pyTony: n/a

Comments
more robust !
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