help for this

[jemz]

hello can you help me how can i print asterisk to form triangle like this

*
                    ***
                   *****
                  *******

here is my code

int main()
 {
   for(i=0;i<10;i++)
    for(j=0;j<i;j++)
     {
      printf("*");
     }
      printf("\n");

     getch()
     return 0;
}

please help me hoping for your positive responds...thank you in advance...

[Auraomega]

You're not going to call your new line with that for loop.

for(i=0;i<10;i++)
  {
    for(j=0;j<i;j++)
    {
      printf("*");
    }
    printf("\n");
  }

Will now give the output:

*
**
***
****
...

So you now need to change the logic to add some spaces to make your * centre. I'll leave that one with you, once you have some updated code if you need any more help post back.

[jemz]

You're not going to call your new line with that for loop.

for(i=0;i<10;i++)
  {
    for(j=0;j<i;j++)
    {
      printf("*");
    }
    printf("\n");
  }

Will now give the output:

So you now need to change the logic to add some spaces to make your * centre. I'll leave that one with you, once you have some updated code if you need any more help post back.

hello sir here's my updated code i just added "\t" so that i can center my * ..sir what should i do now do i need to put another forloop..please help me sir hoping for your positive responds..

for(i=0;i<10;i++)
  {
    printf("\t");
    for(j=0;j<i;j++)
    {
      printf("*");
    }
    printf("\n");
  }

[Auraomega]

As I said, you need to add some formatting to cnetralise the * in each row. Until you have some code to show how you've attempted that I can't really help you.

[jemz]

As I said, you need to add some formatting to cnetralise the * in each row. Until you have some code to show how you've attempted that I can't really help you.

hello sir,

can you give me snippet code for formmatting,i don't have idea on this sir...thank you in advance hoping for your positive responds...

[Adak]

To find the center column for the first *, you can use either the number of rows in the "tree", or the number of *s, in the bottom row.

So if the bottom row has 7 *s, then 7/2 equals 3. So you should have 3 spaces before the * on the first row. You can use a for loop (outer one), to code this:

//handles the outer row configuration
for(numstars=1;numstars<=botmRow;numstars+=2) {
  numspaces = (botmRow - numstars)/2;

  //handles the spaces before the stars
  for(i=0;i<numspaces;i++)
    print one space here

  //prints out the star/s
  for(i=0;i<numstars;i++)
    print out star/s here
}

So the top row could be seen as:

spc spc spc * spc spc spc

because the top row will always have just ONE star. So all the other char's will have to be spaces. :)

Now for each row, the number of stars increases by 2, and that means the number of spaces on each side of the stars, will decrease by 1 (since there are two sides, and 2 * 1 = 2.

imo you don't want to use tabs for this assignment.

[jemz]

To find the center column for the first *, you can use either the number of rows in the "tree", or the number of *s, in the bottom row.

So if the bottom row has 7 *s, then 7/2 equals 3. So you should have 3 spaces before the * on the first row. You can use a for loop (outer one), to code this:

//handles the outer row configuration
for(numstars=1;numstars<=botmRow;numstars+=2) {
  numspaces = (botmRow - numstars)/2;

  //handles the spaces before the stars
  for(i=0;i<numspaces;i++)
    print one space here

  //prints out the star/s
  for(i=0;i<numstars;i++)
    print out star/s here
}

So the top row could be seen as:

spc spc spc * spc spc spc

because the top row will always have just ONE star. So all the other char's will have to be spaces. :)

Now for each row, the number of stars increases by 2, and that means the number of spaces on each side of the stars, will decrease by 1 (since there are two sides, and 2 * 1 = 2.

imo you don't want to use tabs for this assignment.

hello sir thank you for helping me sir it works....more power to you......

[jemz]

To find the center column for the first *, you can use either the number of rows in the "tree", or the number of *s, in the bottom row.

So if the bottom row has 7 *s, then 7/2 equals 3. So you should have 3 spaces before the * on the first row. You can use a for loop (outer one), to code this:

//handles the outer row configuration
for(numstars=1;numstars<=botmRow;numstars+=2) {
  numspaces = (botmRow - numstars)/2;

  //handles the spaces before the stars
  for(i=0;i<numspaces;i++)
    print one space here

  //prints out the star/s
  for(i=0;i<numstars;i++)
    print out star/s here
}

So the top row could be seen as:

spc spc spc * spc spc spc

because the top row will always have just ONE star. So all the other char's will have to be spaces. :)

Now for each row, the number of stars increases by 2, and that means the number of spaces on each side of the stars, will decrease by 1 (since there are two sides, and 2 * 1 = 2.

imo you don't want to use tabs for this assignment.

hello sir thank you for helping me...it works...more power to you...