Member Avatar for singlem1905

today, I want to transform "c:\*\``"(it is a rout) to "c:/*/''"
yes, just from "\" to "/"
but it is always missed ,for example "\n" to "enter"
and how can "c:\*\''" just be "c:\*\''" without changing ?
thanks a lot!

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  • Latest Post Latest Post by TrustyTony

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The behavior seen in the thread is the normal result of Python parsing string literals: backslash sequences like \n are escape sequences and become a newline when the literal is parsed. As pointed out, raw string literals avoid that parsing at source-code time; as requested, showing exact input/output helps diagnose whether the backslash was lost at parse time or came from external input.

When the path is a literal in code, either use a raw literal or escape backslashes. If the string is read from a file or input, Python will keep the backslashes and a simple replace will work. Common, practical options:

# examples of safe literals and conversion
s_bad = "C:\new\test"        # \n becomes newline
s_raw = r"C:\new\test"       # raw literal (note: cannot end with a single backslash)
s_esc = "C:\\new\\test"      # escaped backslashes

s_posix = s_esc.replace("\\", "/")

from pathlib import Path
s_posix2 = Path(s_esc).as_posix()  # modern, cross-platform normalization

Troubleshooting tips: use repr(s) to see the real contents (visible escapes). Remember raw strings are only for literals in source; they do not change already-built strings. Also note that raw strings cannot end with a single backslash, so use escaped forms in that case. For low-level details about literal parsing and a robust path API, see the Python docs on string literals and the pathlib module: Python string literal docs and pathlib — Object‑oriented filesystem paths.

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Member Avatar for TrustyTony

Raw strings could be helpfull.

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