Hi How can I delete a file after a certain time?
for example if I want to delete a file after 08.30 has passed?
do I use import OS? and import time?
Use the wait() method on a Threading.Event object or a Threading.Condition object, with a timeout.
Maybe this could help you to catch some file operation and using time.sleep:
import os import time dirname = 'test' try: os.mkdir(dirname) except: pass fn = os.path.join(dirname, 'test.txt') with open(fn, 'w') as f: f.write('Nothing') print 'Created %s (%s)' % (fn, time.asctime()) print os.listdir(dirname) time.sleep(8.30) os.remove(fn) print os.listdir(dirname) print 'Deleted %s (%s)' % (fn, time.asctime())
It must be in a function. I have 4 files that needs to be deleted within 4 different times. How can I do that then? Can I make it like:
def remove(filename,time) if time os.remove(filename)
I have dont know?
you can sort the times and wait for each time in turn.
What about if the python script not running???
I think you need a cron job. With cron job you are in win win situation for this operation.