guys i made a program and it is working the prob is that it is not displaying the values to in float so guys plz help me in this regard

#include "stdafx.h"
#include<iostream>
#include <stdio.h>

using namespace std ;
void reduce(int&,int&);

class decimal
{
int  numerater;
int denominater;

public :  
decimal():numerater(0),denominater(0)
       {

       }

decimal(int a,int b):numerater(a),denominater(b)
   {
     //cout<<numerater<<endl<<denominater<<endl;
   }
void add(decimal,decimal);
void multi(decimal,decimal);
void divide(decimal,decimal);
void subtract(decimal,decimal);

void show_add ()
{float x=numerater/denominater;
    cout<<"ans of addition of two ratinal function is "<< numerater<<"/"<<denominater<<endl<<"or"<<x<<endl ; }

void show_multi ()
{float y=numerater/denominater;
    cout<<"ans of multi of two ratinal function is "<<numerater<<"/"<<denominater<<endl<<"or"<< y<<endl ; }


void show_divide ()
{float z=numerater/denominater;
    cout<<"ans of divide of two ratinal function is "<< numerater<<"/"<<denominater<<endl<<"or"<<z<<endl ; }

void show_subtract()
{float m=numerater/denominater;
 cout<<"ans of subraction of two ratinal function is "<< numerater<<"/"<<denominater<<endl<<"or"<<m<<endl ; }
};

 void decimal::add(decimal d1,decimal d2)

 {denominater=(d1.denominater*d2.denominater);

 numerater=(d1.denominater*d2.numerater)+(d2.denominater*d1.numerater);

reduce(denominater,numerater); 
show_add ();
}

 void decimal::multi(decimal d1,decimal d2)

{denominater=(d1.denominater*d2.denominater);
numerater=(d1.numerater*d2.numerater);
 reduce(denominater,numerater);
 show_multi();}



void decimal::divide(decimal d1,decimal d2)

{denominater=(d1.denominater*d2.numerater);
 numerater=(d1.denominater*d2.numerater);
 reduce(denominater,numerater);
 show_divide ();}



 void decimal::subtract(decimal d1,decimal d2)

 {denominater=(d1.denominater*d2.denominater);

 numerater=(d1.denominater*d2.numerater)-(d2.denominater*d1.numerater);

reduce(denominater,numerater); 
show_subtract ();
}















int _tmain(int argc, _TCHAR* argv[])
{ 


int a,b,c,d;     
cout<<"enter the value apart from zero\n";
cin>>a>>b;
cout<<"enter the value of other rational no \n";
cin>>c>>d;
reduce(a,b);reduce(c,d);
decimal d1(a,b),d2(c,d),d3;
d3.add(d1,d2);
d3.subtract(d1,d2);
d3.multi(d1,d2);

system("pause");
}

void reduce(int &a,int &b)
 {

     for(int i=1;i<=20;i++)
    {

        for(int j=1;j<=100;j++)   

        {
             if(a%j == 0    &&  b%j == 0)
             {
                a=a/j;
                b=b/j;
             } 
        }
     }
}

Edited 3 Years Ago by Nick Evan: Fixed formatting

the program will take the values and store it in reduced rational form then apply all the artimatic operators on it and display the values in rational and decimal form

**Please use code-tags in the future**

The following expression numerater/denominater is a division of integers, this will be computed with integer arithmetics (the remainder of the division is discarded, i.e. 1 / 2 = 0, 4 / 3 = 1, etc.).

To obtain the answer of the division as a "normal" real-valued division, you need to cast the integers to floating-point values first, and then do the division, i.e. float(numerater) / float(denominater) .

That should fix your problem.

>> how do u use it

How do you use what? Don't make us play 20 questions. If you have a question about Mike's answer, state the question. We don't know what "it" refers to.

This article has been dead for over six months. Start a new discussion instead.