can you give me some search engine code. i am using sql server .. thank in advanced
can you give me some search engine code.
No, You have to show some effort for that first.
Edited 5 Years Ago by debasisdas: n/a
okay sir.. can i have one more favor.. can you please tell me why my program is not working.. this is my sample login program .. the data set is not able to count the data... i wonder why ??
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim connection As New SqlClient.SqlConnection Dim command As New SqlClient.SqlCommand Dim adapter As New SqlClient.SqlDataAdapter Dim dataset As New DataSet connection.ConnectionString = ("Data Source=CUBED-DESKTOP05;Initial Catalog=Biometrics;Integrated Security=True") command.CommandText = " SELECT * FROM (admin) WHERE username= '" & TextBox1.Text & "' AND password= '" & TextBox2.Text & "';" connection.Open() command.Connection = connection adapter.SelectCommand = command adapter.Fill(dataset, "0") Dim count = dataset.Tables(0).Rows.Count If count > 0 Then MsgBox("Welcome to Cubed Technologies", MsgBoxStyle.OkOnly) Form2.Show() Me.Close() Else MsgBox("Incorrect Login please Check your Username and Password") TextBox1.Clear() TextBox2.Clear() Me.TextBox1.Focus() End If End Sub
Edited 5 Years Ago by peter_budo: Keep It Clear - Do use code tags when posting any code
Dim IDNumber As String = Nothing Dim User As String = Nothing Dim Pass As String = Nothing If txtUser.Text = "" Then txtUser.Focus() : MessageBox.Show("Please Enter Username", "Information", MessageBoxButtons.OK, MessageBoxIcon.Information) : Exit Sub If txtPass.Text = "" Then txtPass.Focus() : MessageBox.Show("Please Enter Password", "Information", MessageBoxButtons.OK, MessageBoxIcon.Information) : Exit Sub User = GetFieldValue("SELECT UserName FROM tblUser WHERE UserName = '" & txtUser.Text & "'", "UserName") Pass = GetFieldValue("SELECT Password FROM tblUser WHERE UserName = '" & txtUser.Text & "'", "Password") If User = txtUser.Text And Pass = txtPass.Text Then IDNumber = GetFieldValue("SELECT UserID FROM tblUser WHERE UserName= '" & txtUser.Text & "'", "UserID") UserInfo.IS_USER = IDNumber MessageBox.Show("Login Succesful!", "Welcome", MessageBoxButtons.OK, MessageBoxIcon.Information) Else If Not User = txtUser.Text Then MessageBox.Show("Username not registered", "Invalid", MessageBoxButtons.OK, MessageBoxIcon.Information) Else MessageBox.Show("Invalid Password", "Invalid", MessageBoxButtons.OK, MessageBoxIcon.Information) End If
ohh thank you so much aldeene :) it will help me a lot :)
aldeene's code is a bit random. Why is there code to extract the user name from the database where the userName = txtUser.Text? It will only return what you already have - the entered user name. User is ALWAYS going to equal txtUser.text
All that is really needed is, as you did previously, to select the count of rows in the database where userName = user.Text and password = password.Text. This should provide a count of 1. What error were you getting with that code?
you could try this for your login because you have shown some code.
Dim connection As New SqlClient.SqlConnection Dim command As New SqlClient.SqlCommand Dim adapter As New SqlClient.SqlDataAdapter Dim dataset As New DataSet connection.ConnectionString = ("Data Source=CUBED-DESKTOP05;Initial Catalog=Biometrics;Integrated Security=True") objconnection.Open() 'open connection to server 'this is the SQL select statement query that is performed ' to read the username and password from server Dim SelectStmt As String = "SELECT * FROM users WHERE UserName ='" + TextBox1.Text + "' and " + _ "Password ='" + TextBox2.Text + "'" Dim objcommand As SqlCommand = New SqlCommand(SelectStmt, objconnection) Dim reader As SqlDataReader = objcommand.ExecuteReader If reader.Read Then MainForm.Show 'display login form Me.Dispose()'close login form Else 'integer variable to count the number of times 'the user has tried loggin in Static count As Integer = 0 'display promt Dim prompt As DialogResult = _ MessageBox.Show("Invalid Username or Password!", "Login Error", _ MessageBoxButtons.RetryCancel, MessageBoxIcon.Warning) Select Case prompt Case Windows.Forms.DialogResult.Retry 'keep login displayed for another trial userNameTextBox.Text = "" passwordTextBox.Text = "" count += 1 'increment counter by one If count = 3 Then MessageBox.Show("High value of failed login attempts" & vbCrLf & _ "Application will be terminated" & _ " for security reasons", "Error", MessageBoxButtons.OK, _ MessageBoxIcon.Stop) Application.Exit() End If Case Windows.Forms.DialogResult.Cancel Application.Exit() 'terminate application End Select End If Catch ex As Exception MessageBox.Show("Error: Login Failed for User:" & " " & userNameTextBox.Text) End Try End Sub
i think that code is for vb6 not for vb.net.. that's why its not accept hte other function in vb.net ...
That code is in .net only.
Looking the syntax itself you should be able to know what language it is in.
ohh aldeene there are some errors. is the a vb.net program ??
coz i used a module there, the GetFieldValue line.. hehe sorry I forgot to revised it.. :D
Edited 5 Years Ago by aldeene: n/a
aldeene's code is a bit random. Why is there code to extract the user name from the database where the userName = txtUser.Text?
I did this because what if the user changes his username..
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the function that I created to find the ...
Write a C program that should create a 10 element array of random integers (0 to 9). The program should total all of the numbers in the odd positions of the array and compare them with the total of the numbers in the even positions of the array and indicate ...
Hi. so this is actually a continuation from another question of mineHere but i was advised to start a new thread as the original question was already answered.
This is the result of previous question answered :
code for the listbox - datagridview interaction
At the top of the code ...