Hi, i want to start a process called: notepad.exe wich is a software that windows give you. How do i start that process in a mdi container ?
process.start("notepad.exe"); in mdi container :S
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Jump to PostMaybe this way?:
System.Diagnostics.Process myprocess = System.Diagnostics.Process.Start("notepad.exe");
Jump to PostOr:
Process process = new Process(); process.StartInfo.FileName = @"notepad.exe"; process.EnableRaisingEvents = true; process.Start();
Jump to PostIt is generally not possible to host one application in another; which I think you are trying to do.
If you are trying to write a MDI text editor then you will have to do some of the work.
You can add a TextBox or RichTextBox control to a child …
Jump to PostEach process is a totally separate entity in the Windows OS.
It is possible to have communication between processes, but it is not possible to encapsulate one process inside another to the extent that one appears to be a child window in the other.Although I do not have …
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