#include<stdio.h>
#include<conio.h>
void main()
{
int x=01234;
printf("%d",x);
}

the above c code will produce output 668(value of x) why?

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Read up in your help files, on how int's with assigned values that begin with a zero, are interpreted by your compiler.

What would an assignment of 080 print up?

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Read up in your help files, on how int's with assigned values that begin with a zero, are interpreted by your compiler.

What would an assignment of 080 print up?

Read up in your help files, on how int's with assigned values that begin with a zero, are interpreted by your compiler.

What would an assignment of 080 print up?

the int x=080;
shows illegal octal digit error.

Exactly. The digit "8" does not exist in octal. The digits "1", "2", "3" and "4" do exist in octal.

Compiler treats number starting with 0 as octal number and 01234 is an octal number whose decimal value is 668 as you are printing it with %d specifier so it outputs 668.

check output for this instead:-

printf("%o",x);
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