employee database

[neeraj goswami]

//ASSIGNMENT NO- 4
			//EMPLOYEE DATABASE
#include<stdio.h>
#include<conio.h>
	//STRUCTURE DEFINATION
struct emp1
	{
		int id;
		int dflag;
		char name[10];
		float salary;
	};
int main()
{
	//INITIALISATION
	struct emp1 e[20]={0,0,"\0",0.0};
	int accept(struct emp1 [],int);
	int display(struct emp1 [],int);
	int append(struct emp1 [],int);
	int delete1(struct emp1 [],int,int);
	int modify(struct emp1 [],int,int);
	int no=0,v=0,u=0,ch=0,count=0;
	char ans='\0';
	clrscr();
	do
	{
		printf("\n\t\tMENU");
		printf("\n\t1:ACCEPT");
		printf("\n\t2:DISPLAY");
		printf("\n\t3:APPEND");
		printf("\n\t4:DELETE");
		printf("\n\t5:MODIFY");
		printf("\n\nEnter the choice:");
		scanf("%d",&ch);
		if(ch>2&&count==0)
		{
			printf("NULL INPUT");

		}
		else
		{
		switch(ch)
		{
			case 1:
			printf("\nEnter the of entries u want:");
			scanf("%d",&no);
			if(no==0)
			{
				printf("\nNULL SET");
			}
			else
			{
				printf("\n");
				no=accept(e,no);
				printf("\nNo. of enteries entered=%d",no);
				count=count++;
			}
			break;

			case 2:
			no=display(e,no);
			printf("\nNo. of enteries displayed=%d\n",no);
			break;

			case 3:
			printf("append a record:");
			no=append(e,no);
			no=display(e,no);
			printf("\nNo. of enteries displayed=%d\n",no);
			break;

			case 4:
			printf("Enter the id u want to delete");
			scanf("%d",&u);
			no=delete1(e,no,u);
			no=display(e,no);
			printf("\nNo. of enteries displayed=%d\n",no);
			break;

			case 5:
			printf("Enter the id u want to modify");
			scanf("%d",&v);
			no=modify(e,no,v);
			no=display(e,no);
			printf("\nNo. of enteries displayed=%d\n",no);
			break;

			default:
			printf("\nInvalid entry");
			}}
			printf("\n\nDo u want to contnuie(y/n):");
			flushall();
			scanf("%c",&ans);
			}while(ans=='y'||ans=='Y');
getch();
return(0);
}

int accept(struct emp1 a[20],int n)
{
	float sal=0.0;
	int i=0;
	for(i=0;i<n;i++)
	{
		printf("%d.enter the i.d=",i+1);
		scanf("%d",&a[i].id);
		if(a[i].id==0)
		{
			printf("\n invalid id\n");
			accept(a,n);

		}
		else
		{
		printf("%d.enter the name=",i+1);
		scanf("%s",a[i].name);
		printf("%d.enter the salary=",i+1);
		scanf("%f",&sal);
		a[i].salary=sal;
		}
		printf("pre\n");
	}
	return n;
}

int display(struct emp1 a[20],int n)
{
	int i=0;
	printf("\n");
	printf("\nID\t\tNAME\t\tSALARY ");
	for(i=0;i<n;i++)
	{
		if(a[i].dflag!=-1)

		{
			printf("\n\n");
			printf("%d\t\t%s\t\t%f",a[i].id,a[i].name,a[i].salary);
			printf("\n");
		}
	}
	return n;
}
int append(struct emp1 a[20],int n)
{
if(n==0)
{
	printf("\nEmpty set");
}
else
{
	float sal=0.0;
	printf("enter the i.d=");
	scanf("%d",&a[n].id);
	printf("enter the name=");
	flushall();
	scanf("%s",a[n].name);
	printf("enter the salary=");
	scanf("%f",&sal);
	a[n].salary=sal;
	n++;
	printf("the appended data is:");
}
return n;
}
int delete1(struct emp1 a[20],int no,int u)
{
int i=0;
char ans='\0';
printf("\nAre you sure you want to delete(y/n):");
scanf("%d",&ans);
if(ans=='y'||ans=='Y')
{
	for(i=0;i<no;i++)
	{
		if(u==a[i].id&&a[i].dflag!=-1)
		{
			a[i].dflag=-1;
			break;
		}
	}
}
else if(ans!='y'||ans!='Y')
{
	printf("\n You have not deleted");
}
	return no;
}
int modify(struct emp1 a[20],int n,int v)
{
int i=0;
float sal=0.0;
if(n==0)
{
	printf("\nEmpty set");
}
else
{
	for(i=0;i<n;i++)
	{
		if(v==a[i].id)
		{
			if(a[i].dflag!=-1)
			{
				printf("Enter the new record for the id");
				printf("\nEnter the name:");
				scanf("%s",a[i].name);
				printf("enter the salary:");
				scanf("%f",&sal);
				a[i].salary=sal;
			}
			else
			{
			printf("\nthe record is deleted");
			}
		}
	}
}
return n;
}

[N1GHTS]

Here you go!

#include <stdio.h>

int main(int argc, char** argv) {
    printf("Hello World\n");
    return 0;
}

[Lordvivi]

What is the meaning of this?

[N1GHTS]

What is the meaning of this?

It's obvious that neeraj goswami did not want you to know what this is about, otherwise he would have said something by now. So use this rare opportunity to use your imagination!

I have attached a visual aid of the concept of imagination which may help your interpretation of this thread.

[greatparthi]

HI, N1GHTS, I am not getting

[N1GHTS]

HI, N1GHTS, I am not getting

... and that's okay too. Welcome to Daniweb people. When posting a new thread on this forum, it helps to say something. With nothing to say, a thread can easily become derailed, such as this one.