I have a number of lists such as

I either need to make a list of lists or a dictionary containing lists. What would be the recommended one to do and will make the process of further sorting and text manipulation the easiest.

Thanks,

List is ordered and you mention sorting, so list of lists looks better. Difficult to tell without knowing more of your plans.

I have a loop which generates lists such as

Once all of this have been created within a list of dict I want to print them all out within correctly space|padded columns...

In the end Ive created a list of lists which looks like the following :

[['123', 19, '13', 'Fa0/19', '100000000'], ['13', 22, '13', 'Fa0/22', '100000000'], ['123', 19, '123', 'Fa0/19', '100000000']]

Can you confirm how the for loop would look if I wanted to go through each column by item ?

It is often usefull to do transpose and extract one of the columns which become own list, if you do not want simultanously to process all columns.

from pprint import pprint
info = [['123', 19, '13', 'Fa0/19', '100000000'], ['13', 22, '13', 'Fa0/22', '100000000'], ['123', 19, '123', 'Fa0/19', '100000000']]
print('Info')
pprint(info)
print('Transpose')
pprint(list(zip(*info)))
print('Fa by generator expression')
print(', '.join(fa for a, b, c, fa, d in info))

You can iterate through the list, taking each sub-list and printing the individual items within that sub-list.

test_list=[['123', 19, '13', 'Fa0/19', '100000000'],
           ['13', 22, '13', 'Fa0/22', '100000000'],
           ['123', 19, '123', 'Fa0/19', '100000000']]

for sub_list in test_list:
    print sub_list
    for ctr in range(len(sub_list)):
        print "     ", ctr, "-->", sub_list[ctr]
    print

Edited 5 Years Ago by woooee: n/a

This article has been dead for over six months. Start a new discussion instead.