Does anyone have an algorithm that generates all 10-digit integers that have at least one digit repeated? Trawling through all 9000000000 of them and checking them individually is too slow. Thanks.

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Jump to PostDoes anyone have an algorithm that generates all 10-digit integers that have at least one digit repeated? Trawling through all 9000000000 of them and checking them individually is too slow. Thanks.

10 digit number, 10 digits, none repeated, sounds like you can generate all permutations of 0123456789, then throw out …

Jump to Post10! is 3,628,800. 10 to the 10th power is 10 billion. Take away the numbers that start with 0 and that's what you're working with. You have, again, two options. One way or another, you have a loop of 9 billion if you need to "pop out" a number each …

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