C++ infinite loop problem , please help?

[infamous5]

Hello, I am a beginner at programming and I am having some trouble finding the error in my code(pasted below). I am first trying to come up with a (1) function to evaluate integers at a given power.(2) A function to check if an integer is a perfect number. I do this by trying to use the formula N=2(k-1)*((2^k)-1). This formula only works for certain values of k so you have to do another check within the function. I look to see if the sum of the divisible numbers of the integer add up to the integer. Like 6= 1+2+3. Then I look to see if N and the sum equal each other. Note: I stop the sum of divisors once the sum becomes higher than the integer were checking.
(3) Then I make a function that will display the sum of all the divisible numbers like "6 = 1 + 2 + 3". (4) then I try to put everything together by using an infinite for loop till I find the first five perfect numbers. Can you help me see were I went wrong, Id really appreciate it.

#include <iostream>
using namespace std;

int ipow(int a, int b)
{
   int i = 1, j = a;
   while(i < b)
   {
      a = a*j;
   }
   if(b == 0)
   {
      return 1;
   }
   else
   {
      return a;
   }
}

bool PerfectNumCheck(int a)
{
   int sum = 0, k = 2, N = 0, b, c;
   for (int i = 1; i <= (a - 1); i++)
   {
      if(a%i == 0)
      {
         sum = sum + i;
      }
      if(sum > a)
      {
         i = a;
      }
   }
   while(N < a)
   {
      b = ipow(2, k - 1);
      c = ipow(2, k) - 1;
      N = b*c;
      k++;
   }
   if(N == sum)
   {
      return 1;
   }
   else
   {
      return 0;
   }
}

int ProperDivisor(int a)
{
   int sum = 0;
   cout << a << " = ";
   for(int i = 1; i <= (a-1); i++)
   {
      if(a%i == 0)
      {
         sum = sum + i;
         if(sum < a)
         {
            cout << i << " + ";
         }
         if (sum == a)
         {
            cout << i << endl;
            i = a;
         }
      }
   }
   return 0;
}

int main(void)
{
   int n = 0, check;
   for (int i = 2; ; i++)
   {
      check = PerfectNumCheck(i);
      if (check)
      {
         cout << i << " is a perfect number \n";
         ProperDivisor(i);
         cout << endl;
         n++;
      }
      if (n == 5)
      {
         return 0;
      }
   }
}