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How do i convert the list to

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  • Latest Post Latest Post by Gribouillis

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As wanted to turn a list of single characters into a list of words, and as pointed out, the common approach is to combine the characters into a string and split on whitespace. That is simple and efficient for normal text; here are a few alternative patterns, edge cases to watch for, and ready-to-use snippets that avoid repeating the exact one-liner already shown.

A memory-friendly, linear scanner that builds words as it iterates (no intermediate full-string split) — good for streaming or very large inputs:

chars = ['h','e','l','l','o',' ','w','o','r','l','d']
words = []
buf = []
for ch in chars:
    if ch.isspace():
        if buf:
            words.append(''.join(buf))
            buf = []
    else:
        buf.append(ch)
if buf:
    words.append(''.join(buf))
# words -> ['hello', 'world']

If brevity matters and the input is a sequence of characters, itertools.groupby provides a concise expression:

import itertools
words = [''.join(group) for is_space, group in itertools.groupby(chars, key=str.isspace) if not is_space]

To extract only alphanumeric tokens and drop surrounding punctuation, use the regex approach (works after creating a string):

import re
s = ''.join(chars)
words = re.findall(r'\b\w+\b', s)

Notes and pitfalls: handle tabs/newlines by using str.isspace() (it recognizes common whitespace); be explicit about how you want to treat punctuation (keep it or strip it); for Unicode-heavy data ensure you’re working with proper text strings (Python 3). For reference on the standard behaviors, see the string method docs and the regex module docs: str.split / str.join documentation and re — regular expressions.

Member Avatar for Gribouillis

Hm ''.join(the_list).split()

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