I need some help understanding the follow functions & how they work.
1) y >> 16 & 0xFF0
2) (y >> 16 & 0xFFC) << 4
3) (y >> 20 & 0xF0F) | 1 << 7
ashboi
0
Newbie Poster
Recommended Answers
Jump to PostWhat do you think they do? If you try to explain them, we'll tell you where you got it wrong.
Jump to PostCorrect on the first 2.
Wrong on last one. There's no compare and no XOR...But what do they mean
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WaltP
2,905
Posting Sage w/ dash of thyme
Team Colleague
What do you think they do? If you try to explain them, we'll tell you where you got it wrong.
ashboi
0
Newbie Poster
well, from what I know, the
1st one is
shift y by 16 & 0xFF0
2nd is
shift y by 16 & 0xFFC then shift left by 4
3rd
shift y by 20 & 0xF0F then comparing with 1 using XOR & then shift left by 4
pls let me know if im wrong here
WaltP
2,905
Posting Sage w/ dash of thyme
Team Colleague
Correct on the first 2.
Wrong on last one. There's no compare and no XOR...
But what do they mean
nullptr
167
Occasional Poster
Just using the first example:
y >> 16 & 0xFF0 // y is shifted right by 16 bits, then bitwise and with bitmask 0xFF0
e.g 0xBEEFC000 >> 16 = 0xBEEF
0xBEEF & 0xFF0 = 0xEE0
rubberman
1,355
Nearly a Posting Virtuoso
Featured Poster
FWIW, the XOR operator is ^ as in (0xCAFEFACE ^ 0xECAFEFAC). The | symbol is the OR operator.
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