Just taking the first part of the equation - 3x^3
To multiply you need to use * as in 3*x
^ is bitwise xor, do you really want to calculate 3 times x xor 3? Read More

Just taking the first part of the equation - 3x^3
To multiply you need to use * as in 3*x
^ is bitwise xor, do you really want to calculate 3 times x xor 3?

Thanks managed to solve it.But just 1 more question, if i want to make x the constant or in c u call define.,how can i go about? Below is my solved equation

Code blocks are created by indenting at least 4 spaces
... and can span multiple lines

include<stdio.h>

include<stdlib.h>

include<math.h>

int main(void)
{

double x=2.55;
double polynomial=3.0*x*x*x-5.0*x*x+6.0; /*this is similar to 3.0*pow(x,3)-5.0*pow(x,2)+6;*/
printf("The value of polynomial is %lf\n",polynomial);
system("pause");
return(EXIT_SUCCESS);

}

Code blocks are created by indenting at least 4 spaces
... and can span multiple lines

I am looking for log archival utility or approach which should be able to help me in based on below policy.
(1) whenever log file (system.log) size >30859 or file ...

Good day community,
I have completed vb.net program (a school timetabling program) and I am in the process to create a website. At the moment word -press on wamp server ...