Hi, everyone.
Hope you can help me to answer the question,
i am not familiar with recursive function...and i hope someone could help me..

Shift elements means
e.g.

array[ ] = {1, 2, 3, 4, 5, 6};
if the user input a value, say 2,
the array will become {5, 6, 1, 2, 3, 4},
the elements shift to the right by 2;

You may see the file attached as reference.

array1

Thanks.

Attachments array.png 142.36 KB

A recursive function calls itself with slightly modified parameters from those it was called with.
Here's an example of a recursive function.

unsigned long factorial(unsigned long n){
    if(n>1)
        return factorial(n-1);
    else
        return 1;
}

Edited 4 Years Ago by diafol: Can't edit/delete as replies have been posted since your post. This could break the thread. Sorry.

That means the answer to my question should be

void move(int array[ ], int n, int m) {
     if (m == 0)
         return;
     else
         return move(array, n, m - 1);
}

???

I try it before, but it doesn't work

#include <stdio.h>

void move(int array[], int n, int m);

int main(void) {
    int number[8] = {1, 2, 3, 4, 5, 6, 7, 8};
    int n= 8;
    int m;
    int i;

    printf("How many place you want to move?");
    scanf("%d", &m);

    move(number, n, m);
    printf("The resulting array is:\n");
    for(i = 0; i < n; i++) {
        printf("%d ", number[i]);
    }
    printf("\n");

    getchar();
    getchar();
    return 0;
}

void move(int array[], int n, int m)
{
    int i;

    if(m == 0) {
        return;
    }else {
        move(array, n, m-1);
        if(i+m>n) {
            array[i+m] = array[i+m-n];
        }
        array[m-1] = array[m];

    }

}

This is my attempt and it fails again...
can anyone tell me where is my mistake??

You're definitely on the right track.

void move(int array[], int n, int m)
{
    int i;

    if(m == 0) {
        return;
    }else {
        move(array, n, m-1);
        if(i+m>n) {
            array[i+m] = array[i+m-n];
        }
        array[m-1] = array[m];

    }

}

Now tell us what your i variable is supposed to do? You're reading from it (the i+m>n counts as a read) before you give it a value. Which is a no-no. Also, you're not changing it in any way. The key to this is fixing the i. And you probably need a temporary value somewhere to hold what you're over-writing.

Lastly, I screwed up on my earlier attempt to explain a recursive function. The web browser ate my post, and I had to redo it. Well, the second time around, I was annoyed and not nearly as cautious.

unsigned long factorial(unsigned long n){
    if(n>1)
        return factorial(n-1);
    else
        return 1;
}

Should be:

unsigned long factorial(unsigned long n){
    if(n>1)
        return n*factorial(n-1); //notice the "n*"
    else
        return 1;
}

I had to flag my own post as bad. :(

is it necessary that you use recursion ? i have another code for the same try it

#include<iostream.h>
#include<conio.h>

void main()
{
int A[100],B[100];
int n,c,i,r;
cout<<"\n Enter the size : ";
cin>>n;
cout<<"\n Enter the array : ";
i=0;
while(i<n)
{
cin>>A[i];
i++;
}
for(i=0;i<n;i++)
B[i]=A[i];
cout<<"\n Enter the rotation factor : ";
cin>>r;
for(i=0;i<n;i++)
{
c=(i+r)%n;
A[c]=B[i];
}
cout<<"\n The updated array is : ";
for(i=0;i<n;i++)
cout<<A[i]<<"\t";
getch();
}
Comments
fantabulous!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

just try it

#include<iostream.h>
#include<conio.h>

void main()
{
int A[100],B[100];
int n,c,i,r;
cout<<"\n Enter the size : ";
cin>>n;
cout<<"\n Enter the array : ";
i=0;
while(i<n)
{
cin>>A[i];
i++;
}
for(i=0;i<n;i++)
B[i]=A[i];
cout<<"\n Enter the rotation factor : ";
cin>>r;
for(i=0;i<n;i++)
{
c=(i+r)%n;
A[c]=B[i];
}
cout<<"\n The updated array is : ";
for(i=0;i<n;i++)
cout<<A[i]<<"\t";
getch();
}
Comments
good dani
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