I can't seem to see how this slice works

``````test = (1,2,3)
>>> test[::2]
(1, 3)
``````

The Python's slicing operator can be used with any indexed sequence like strings, lists, ...
syntax --> seq[begin : end : step]
step is optional
defaults are index begin=0, index end=len(seq)-1, step=1
step = -1 reverses sequence

still haveing trouble understanding it :-) in my example what are the start, stop and reverse sequence

in sequence (1, 2, 3)[::2]
the start is element 1
the end is element 3
and step is 2 so it skips the second element (happens to be 2)

Perhaps this gives more insight ...

``````>>> (1,2,3,4,5,6,7,8)[::2]
(1, 3, 5, 7)
>>>
``````

Even though 8 is the end it gets skipped by step=2

What do you think would be the result of ...

``````(1,2,3,4,5,6,7,8,9)[::-2]
``````

or

``````(1,2,3,4,5,6,7,8)[::-2]
``````

?

I figured correctly and verified with the interpreter.

now very clear. I appreciate your help :-)

There is a way to ask python what are start, stop and step:

``````>>> s = slice(None, None, -2) # a slice object corresponding to [::-2]
>>> s.indices(8)
(7, -1, -2) # start, stop, step if the slice is applied to a tuple of length 8
``````