Hello, I have the following pseudo code that I am trying to implement in Java. My issue is the pseudo code seems to be heavily C based and my C is very rusty. Could someone help me understand the following function?

uint theFunction(BYTE* header)
    UINT length;

    header = header + 1;
    length = ((UINT16) header[0]) | ((UINT16) header[1] << 8);

    return length;

My issues are mostly with the understanding of the header = header + 1; and the length = ((UINT16) header[0]) | ((UINT16) header[1] << 8);. I am assuming the header pointer is increasing to the 2nd byte and then the 3rd and 4th bytes are being or'd together after shifting the 4th...

It wants an array of bytes and extracts a "length" value from that array by combining the bits in the second and third byte to form a 16 bit integer. (later stored in a 32 bit one..)

The most significant part of this 16-bit integer is formed by the third byte, the least significant section by the second byte.


example. Say you have this array as input, showing each byte as 8 bits.

[0000 0000][0101 0101][1111 0000]

The function would then produce a 16 bit integer like this:

[1111 0000 0101 0101]

This is stored into a 32-bit integer and then returned.

Edited 4 Years Ago by Gonbe

Perfect explaination
This question has already been answered. Start a new discussion instead.