hello guys,

i want to write a program to cout the numbers i input (a-z) to (z-a)
like

input (1,2,3,4,5,6,7,8,9,10)
output(10,9,8,7,6,5,4,3,2,1)

and i tried this but it's out put the same sorting

    #include <iostream.h>

    void main(void)
    {
        int Number[11],i,j;

    cout<<"Enter The Numbers"<<endl;

    for (i = 1; i<=10; i++)
    {
        cout<<"Number"<<i<<": ";
        cin>>Number[i];

    }
     for (j=1;j<=10;j++)
     {
     cout<<Number[j]<<endl; 

     }



    }

That's because you're typing them in the order:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10

And you're outputting them in the same order.
Take a closer look at how you have your second loop setup.

That's because you're typing them in the order:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10

And you're outputting them in the same order.
Take a closer look at how you have your second loop setup.

yes i don't know how to make it, so please guide me :)

Edited 4 Years Ago by magdy.elbaset

omg i've fixed it

    void main(void)
    {
        int Number[11],i,j;

    cout<<"Enter The Numbers"<<endl;

    for (i = 1; i<=10; i++)
    {
        cout<<"Number"<<i<<": ";
        cin>>Number[i];

    }
     for (j=10;j>=1;j--)
     {
     cout<<Number[j]<<endl; 

     }



    }

^^

It is int main() not void main(void) and #include <iostream> not ...<iostream.h>

it is int main() not void main(void) and #include <iostream> not

void) and #include <iostream> not

It is int main() not void main(void) and #include <iostream> not ...<iostream.h>

what's the diference ?

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