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int d=num%10; 
rev= (rev*10)+d; 
num=num/10;

//Why is it reverse? please explain.

Edited by peter_budo because: Code formatting
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Member Avatar for JamesCherrill

That is part of a loop that will reverse the digits in a number. It makes no sense without the loop.
To see how it works, pick a number and go through that code by hand working out the results for each line.

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