i am trying to Calculate the physical memory address generated by the following segment offset pairs. please you check my solution. thanks
Answer:
a. 1DDDh:0436h 1E206
b. 1234h:7920h 19C60
c. 74F0h:2123h 77023
d. 0000h:6727h 06727
e. FFFFh:4336h 104326=04326
f. 1080h:0100h 10900
g. AB01h:FFFFh 1AB00
Dear shahid your question is a to f is correct but g is wrong and correct is
AB01h:FFFFh BB00F
what kind of operation you must do between 1DDD and 0436 to get 1E206 :eek: ? thanx
Hi uu666,
This operation:
http://mirror.href.com/thestarman/asm/debug/Segments.html
means:
Absolute Memory Location = (Segment Value * 16) + Offset value
Good luck.
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