Member Avatar for saurabh.mehta.33234 
  #include<stdio.h>
  int i=5;
  main()
  {
 int i=6;
  {

    int i=7;
    printf("%d",i);

  }
   printf("%d",i);
  }

Why does the above code doesnot give a variable redifinition error..Although the variable i is defined outside of block also??

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  • Latest Post Latest Post by Moschops
Member Avatar for Moschops

You are allowed to redefine a variable inside a deeper scope. This is commonly called "shadowing" and it's generally regarded as a bad idea.

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