Hello, I'm a newbie in C/C++ programming and I wonder if you can make me understand the following, I have a small c++ statement, and the result is somehow weird for me:
char[10] arr="torino", *ptr;ptr = arr;cout<<&&ptr;`
and the result gives me the entire string....
PS: This is not related to an assignment.
Thanks in advance
Jump to PostIs this what you meant?
char[10] arr="torino"; char* ptr; ptr=arr; cout << *&*&ptr;Also, this looks like C++. Next time, post it in the C++ forum :)
Jump to Post
ptris an object of type char*.&ptris a pointer to the object ptr, so an object of type char** (pointer to a char pointer)*&ptris the object that&ptris pointing to, so it's ptr again.
So*&*&ptris the same as*&ptr.
Do that again, and it's clear …
in the cout statement, there are two missing stars *, one befoe the first & and one before the second.
Is this what you meant?
char[10] arr="torino";
char* ptr;
ptr=arr;
cout << *&*&ptr;
Also, this looks like C++. Next time, post it in the C++ forum :)
I'm glad that you find my typo, that I've also specified in a reply, this is my first post. If you can help me understand, I will be glad. :)
ptr is an object of type char*.&ptr is a pointer to the object ptr, so an object of type char** (pointer to a char pointer)*&ptr is the object that &ptr is pointing to, so it's ptr again.
So *&*&ptr is the same as *&ptr.
Do that again, and it's clear that *&*&ptr is the same as ptr
So cout << *&*&ptr; is the same as cout << ptr;
Is that clear?
Yes, thank you very much!!! ~_~
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