Hello,

I am in learning java. I try this code that I got from internet :

static void insertionSort(int[] A) {
      // Sort the array A into increasing order.

   int itemsSorted; // Number of items that have been sorted so far.

   for (itemsSorted = 1; itemsSorted < A.length; itemsSorted++) {
         // Assume that items A[0], A[1], ... A[itemsSorted-1] 
         // have already been sorted.  Insert A[itemsSorted]
         // into the sorted part of the list.

      int temp = A[itemsSorted];  // The item to be inserted.
      int loc = itemsSorted - 1;  // Start at end of list.

      while (loc >= 0 && A[loc] > temp) {
         A[loc + 1] = A[loc]; // Bump item from A[loc] up to loc+1.
         loc = loc - 1;       // Go on to next location.
      }

      A[loc + 1] = temp; // Put temp in last vacated space.
   }
}

I want to try this to print the result, so I modify this code to :

public class InsertionSort {

    public static void main(String[] args) {
        int[] A = {2, 7, 1, 9, 5, 12, 3};
        insertionSort(A);
    }

    static void insertionSort(int[] A) {
          // Sort the array A into increasing order.

       int itemsSorted; // Number of items that have been sorted so far.

       for (itemsSorted = 1; itemsSorted < A.length; itemsSorted++) {
             // Assume that items A[0], A[1], ... A[itemsSorted-1] 
             // have already been sorted.  Insert A[itemsSorted]
             // into the sorted part of the list.

          int temp = A[itemsSorted];  // The item to be inserted.
          int loc = itemsSorted - 1;  // Start at end of list.

          while (loc >= 0 && A[loc] > temp) {
             A[loc + 1] = A[loc]; // Bump item from A[loc] up to loc+1.
             loc = loc - 1;       // Go on to next location.

          }

          A[loc + 1] = temp; // Put temp in last vacated space.

       }

          for (int i=0; i <= A.length; i++){           
              TextIO.putln(A[i]);
          }
    }

}

But, it was give me this :

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 7
at InsertionSort.insertionSort(InsertionSort.java:33)
at InsertionSort.main(InsertionSort.java:6)
1
2
3
5
7
9
12

What is the mean of this error notification ?

exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 7
at InsertionSort.insertionSort(InsertionSort.java:33)
at InsertionSort.main(InsertionSort.java:6)

Thank you

Recommended Answers

All 2 Replies

Remember that Java like C uses "zero based" arrays. That means that if an array has 7 elements, it's indices go from 0 to 6. With i<=A.length, you're setting i to 0 through 7. But A[7] doesn't exist. Hence the out of bounds exception.

            //Change i<=A.length to i<A.length
            for (int i=0; i < A.length; i++){
                  TextIO.putln(A[i]);
            }

Ah, thank you very much.

I am really sorry. I am never learn C. I am just learn from internet :)

Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.