One step flaw! Count issue in game

[Pioggia254]

Hello! I am a newbe to python and apologize in advance for this question, because I am sure it is an easy fix that I am oblivious too -
I wrote this simple program for a guessing game- very basic, which is fine - but when you get to the end of the game, and guess the correct number, the number of tries is off by ONE - it is driving me mad! here is what the code consists of (runs fine aside from that flaw)

count = 0
secret = random.randint (1, 100)

print ("Guessing game - Guess my secret number - number between 1-100")
guess = int(input("Your Guess?"))
while (guess != secret):


    if (guess > secret):
        print ("Your guess is higher")
        guess = int(input("Guess again:"))

    elif (guess < secret):
        print ("Your guess is lower")
        guess = int(input("Guess again:"))

else:
    print ("You Guessed it!It took you", count, "tries.")

[Pioggia254]

line 7 should have the indented
count = count + 1
not sure why it didn't show up

[woooee]

You want to increment count after every input. You do not increment it after the first input statement. Also the final else is not necessary.

import random

count = 0
secret = random.randint (1, 100)

print ("Guessing game - Guess my secret number - number between 1-100")
guess = int(input("Your Guess? "))
count +=1     ## <----------------- or count=1
while (guess != secret):
    count += 1

    if (guess > secret):
        print ("Your guess is higher")
        guess = int(input("Guess again:"))

    elif (guess < secret):
        print ("Your guess is lower")
        guess = int(input("Guess again:"))

print ("You Guessed it!It took you", count, "tries.")

[Pioggia254]

Awesome! Thank you for your help!

[TrustyTony]

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[sneekula]

You may want to help the user in case of an invalid integer entry.

[vegaseat]

The line
guess = int(input("Your Guess? "))
in essence appears 3 times, see if you can use it just once.