i have declared two functions of void type.lets one function calculates value of variable 'c' and other of variable 'y' and when i cout them it comes out to be correct within the function.now i want to declare another function that compares values of 'c' and 'y' and return 1 if c=y and return 0 otherwise.please help and also i m a beginner in c++.
functions
1
Ancient Dragon 5,243 Change the return type of each function to return the value of c and y, then in the third function you can get those values to compare them. Something like this:
int foo1()
{
int c = 5;
return c;
}
int foo2()
{
int y = 0;
return y;
}
int foo3()
{
int c = foo1();
int y = foo2();
return c == y; // returns either 1 or 0 (true or false)
}
Edited by Ancient Dragon
0
Learner010 99 return 1 if c=y and return 0 otherwise
for this , you need to declare a function of int return type.
function that compares values of 'c' and 'y'
just use == operator.
if(c==y)
return 1;
else
return 0;
Edited by Learner010: AD Solution is far better. i didn't see the AD's reply when i read this thread.
1
panqnik You might also do like this:
int foo1() {
return 2;
}
int foo2() {
return 2;
}
bool areEqual() {
return foo1() == foo2();
}
It's worth to mention sequence points in C++, luckily it was on of my latest post on my blog:
http://blog.panqnik.pl/dev/sequence-points-in-c-cpp/
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