0

Develop a logic in java to find out these two numbers series composed by

First number is - 98 Second is-76

How to develop a logic

Another series - 1213,121312,1313,1212,12131213 First Number-12 Second Number-13

Not Yet Answered # Series

JamesCherrill 2,785 milil 24 Discussion Starter anita_2 milil 24 Discussion Starter anita_2 milil 24 Discussion Starter anita_2 JamesCherrill 2,785 Hey, so I wanna ask how I need to create a method who will remove word if in that word is 2 same chars. Example: "Potato" in this word there is a 2 "o" chars so this word will need to be removed. "Forum" in this word there is no ...

0

Develop a logic in java to find out these two numbers series composed by

First number is - 98 Second is-76

How to develop a logic

Another series - 1213,121312,1313,1212,12131213 First Number-12 Second Number-13

0

There are lots of people here who will freely give their time to help you become the best Java programmer you can be. There's nobody here who is interested in helping you cheat or doing your homework for you.

DaniWeb Member Rules (which you agreed to when you signed up) include:

"Do provide evidence of having done some work yourself if posting questions from school or work assignments"

http://www.daniweb.com/community/rules

Post what you have done so far and someone will help you from there.

-1

If it is a array it will be something like this.

```
int array [] = {9876,7698,7676,9898,987698,769876};
for (int x = 0; x < array.length; x++) {
String number = array[x] + "";
String firstTwoNumbers = number.substring(0,2);
int numberLength = number.length();
String lastTwoNumbers = number.substring(numberLength - 2, numberLength);
if (firstTwoNumbers.equals("98")) {
// it starts with 98...
}
if (lastTwoNumbers.equals("76")) {
// it ends with...
}
}
```

-1

But these number can be anything its not defined that series is made by which number than how to do it.

Or we dont know that number is 2 digit number it can be 1 digit or can be 3 digit.

Like series can be like this-79,97,77,99,777999,999777 Than

0

It can be anything you want it don't need to be array, and you don't need to worry about digits beucause this work like this:

String number = array[x] + "";

It makes string from number.

String firstTwoNumbers = number.substring(0,2);

It will get first two letters from that string, for example:

String number is "97112681919"

firstTwoNumbers will be: 9 (position 0) 7 (position 1) so you will get: 97

int numberLength = number.length();

This will calculate how much digits you have it can be 0 od 10000...0000 .

String lastTwoNumbers = number.substring(numberLength - 2, numberLength);

For last example "97112681919" it has 11 digits so what will this line code do. It will make substring from numberLength that is 11 - 2 so you get 9 and numberLength that is 11 so you will get string from 9 to 11 and that is digit on position 9 and position 10 so you will get: 19

If it can be anything you will need scaner to get input from your keybord and you need to define numbers and "compose numbers" so you can calculate.

-1

Problem is-

An Input series has 20 numbers composed by basic two numbers

1> which are these two numbers

2> how many times number1 and numbers2 has occured.

3> how many occurences they have in given 20 numbers.

4> in one occurence max time each one has occured .

5> which one is occured more number of times.

6> which one is occured maximum number of times in one occurence and how many times

1

I give you something to work with, when you write something your own and find a problem i will help you.

1

I wrote this but not working

```
int num=121121;
int i=1,Fnum,UpNum;
int LastDigit=num%10; //6
UpNum=LastDigit;
Fnum=UpNum;
System.out.println("First Number is"+Fnum+"LastDigit"+LastDigit);
int RDigit=num/10; //98987
System.out.println("LastDigit = "+LastDigit+" RDigit="+RDigit);
String str=Integer.toString(num);
System.out.println("str length"+str.length());
while(i<str.length())
{
String substr=Integer.toString(LastDigit);
if(str.contains(substr))
{
int SecLastDigit=(int) (RDigit%Math.pow(10, i));
UpNum=LastDigit+(int) (SecLastDigit*Math.pow(10, i));
RDigit=RDigit/10;
System.out.println("UpNum"+UpNum);
System.out.println("RDigit"+RDigit);
Fnum=UpNum;
i++;
System.out.println("First Number is"+Fnum);
}
else
{
Fnum=UpNum;
}
break;
}
```

0

This looks like a case of premature coding.

There's no way you will magically come up with the right code if you don't understand the algorithm it implements.

The way to understand (or create) an algorithm is to work through it on paper.

I would get some paper and solve one or two actual problems by hand. Then look back and see how you did that... now you have a starting point for the algorithm.

ps: It's the first time I've seen this particular problem. It's very interesting. What are the constraints on the basic 2 numbers...

are they the same length or could they be (eg) 123 and 45?

can one be a subset of the other, eg 1234 and 23? (tricky, that one)

is there any reason why they are numbers not just arbitrary Strings?

This article has been dead for over six months. Start a new discussion instead.

Recommended Articles

I am writing a java program that needs to execute shell commands, so I wrote a function that would take the command to execute as a string (ie: "mkdir ~/Folder1") and execute that command with the shell. Here is the function:

```
try
{
Runtime run = Runtime.getRuntime();
Process pr = ...
```

Help! I want to create a java program that finds the highest even integer among the values entered by the user. Stop asking values when a value less than 1 have been entered. If no even integer is entered, display "No Even Integer"

Here is the sample output that I ...