how to create a arry that stores the first 100 multiples of a user-supplied integer, prints the values forward and backwarf rom storage (in an array); prints any values that are multiples of a second user-supplied integer or a message indication that there are no multiples of tha number if that is so

## All 4 Replies

To get ye' started, here is how to create an array and store the first 100 multiples of a number into that array

(assuming that no number in the array exceeds the bounds of the datatype size int )

``````int array[100] ;

cout << "Enter a number: " ;
cin >> array[0] ;

for (int i=0; i<99; i++)

array[i+1] *= array[i] ;``````

at this point, you have a populated array of integers. how you want to test the array.. and display it is up to you.

That only generates 99 numbers. You should have "i<100".

That only generates 99 numbers. You should have "i<100".

Nope i think it is alright since he has initially assigned the first element of the array with the value from `cin >> array[0];` and the remainig 1 to 99 elemets get assigned values from the statement

``````for (int i=0; i<99; i++)
array[i+1] *= array[i] ;``````

Hope i am right.

> `array[i+1] *= array[i] ;` Since this is just short for `array[i+1] = array[i+1] * array[i] ;` All the calculations involve undefined values because i+1 element is read before being written (in the absense of any other initialisation).

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