Problem with my menu...

[TObannion]

So I am making the menu for a rock paper scissors game, and it's working other than the quit function in the main menu.
I know that it's because the blank space used for enter is considered a string, but the assignment requires that I use enter to quit from the main menu. Can someone show me the operation I am missing that tells IDLE to take a string as input? or how to possibly convert it from a string to an int?
Here's my code:

def menuMain():
    print("--------------------------------------------------------")
    print(" Welcome to the wonderful world of Paper Rock Scissors! ")
    print("--------------------------------------------------------\n")
    print(" 1) One Player Game ( One human playing against the computer.) \n")
    print(" 2) Enter for a Two Player Game ( Two humans playing against each other.) \n")
    print(" Choose game type or press ENTER to quit game. \n")
    print("-----------------------------------------------")
    menuChoice = eval(input(" Please enter a choice from the above menu: \n-----------------------------------------------\n"))


    if (menuChoice == 1):

        print(" You have decided to play a one player game against the computer. \n")
        print(" 1) Paper \n")
        print(" 2) Rock \n")
        print(" 3) Scissors \n")
        print(" 4) Quit \n")
        subMenuChoice = eval(input( "Please choose from the above weapons menu: \n"))
        if( subMenuChoice == 1):
            print(" You have chosen Paper. ")
        elif(subMenuChoice == 2):
            print(" You have chosen Rock. ")
        elif(subMenuChoice == 3):
            print(" You have chosen Scissors. ")
        elif(subMenuChoice == 4):
            print(" You have chosen to quit. ")
            return 0
        else:
            print(" Invalid menu choice. ")

    elif (menuChoice == 2):
        print (" You have decided to play a two player game against another human. ")
        print(" 1) Paper \n")
        print(" 2) Rock \n")
        print(" 3) Scissors \n")
        print(" 4) Quit \n")
        subMenuChoice = eval(input(" Please choose from the above weapons menu: \n"))
        if( subMenuChoice == 1):
            print(" You have chosen Paper. ")
        elif(subMenuChoice == 2):
            print(" You have chosen Rock. ")
        elif(subMenuChoice == 3):
            print(" You have chosen Scissors. ")
        elif(subMenuChoice == 4):
            print(" You have chosen to quit. ")
            return 0
        else:
            print(" Invalid menu choice. ")
    elif (menuChoice == ""):
        print (" Quitting game. Thank you for playing, please play again soon. ")
        return 0
    else:
        print(" Invalid menu choice. ")

menuMain()

Please just help me with this part...I'm not interested in hearing how I can shorten everything up, I'm trying to build this from the ground up first.
Thanks

[TObannion]

Okay so, as I've heard it happens so many times, I walked away for a bit and it hit me while giving my son a bath...I changed the input to just input, and used the numbers as strings in my if else statements. I'll post my code for reference:

def menuMain():
    print("--------------------------------------------------------")
    print(" Welcome to the wonderful world of Paper Rock Scissors! ")
    print("--------------------------------------------------------\n")
    print(" 1) One Player Game ( One human playing against the computer.) \n")
    print(" 2) Enter for a Two Player Game ( Two humans playing against each other.) \n")
    print(" Choose game type or press ENTER to quit game. \n")
    print("-----------------------------------------------")
    menuChoice = (input(" Please enter a choice from the above menu: \n-----------------------------------------------\n"))


    if (menuChoice == "1"):

        print(" You have decided to play a one player game against the computer. \n")
        print(" 1) Paper \n")
        print(" 2) Rock \n")
        print(" 3) Scissors \n")
        print(" 4) Quit \n")
        subMenuChoice = eval(input( "Please choose from the above weapons menu: \n"))
        if( subMenuChoice == 1):
            print(" You have chosen Paper. ")
        elif(subMenuChoice == 2):
            print(" You have chosen Rock. ")
        elif(subMenuChoice == 3):
            print(" You have chosen Scissors. ")
        elif(subMenuChoice == 4):
            print(" You have chosen to quit. ")
            return 0
        else:
            print(" Invalid menu choice. ")

    elif (menuChoice == "2"):
        print (" You have decided to play a two player game against another human. ")
        print(" 1) Paper \n")
        print(" 2) Rock \n")
        print(" 3) Scissors \n")
        print(" 4) Quit \n")
        subMenuChoice = eval(input(" Please choose from the above weapons menu: \n"))
        if( subMenuChoice == 1):
            print(" You have chosen Paper. ")
        elif(subMenuChoice == 2):
            print(" You have chosen Rock. ")
        elif(subMenuChoice == 3):
            print(" You have chosen Scissors. ")
        elif(subMenuChoice == 4):
            print(" You have chosen to quit. ")
            return 0
        else:
            print(" Invalid menu choice. ")
    elif (menuChoice == ""):
        print (" Quitting game. Thank you for playing, please play again soon. ")
        return 0
    else:
        print(" Invalid menu choice. ")

menuMain()

If anyone would still like to tell me if it's possible to make Python accept a string as eval input, I would love to know...Thanks

[Josiah_2]

do you mean like this:

def main():
    menu = raw_input("choose rock, paper, or scissors: ")
    if menu == "rock":
        print "Rock"
    elif menu == "paper":
        print "Paper"
    elif menu == "scissors":
        print "Scissors"
    else:
        print "Invalid selection"

main()

this would allow you to check string

[Josiah_2]

I would also build in some error handling and user input handling such as have it set the raw_input given to .lowercase or .uppercase to ensure that if the user types Rock it will be treated the same as rock or rOCk for instance

[vegaseat]

In Python3 the input() function returns a string.
If you want an integer you use int(input()).