Guys i cant imagine about how i'm gonna calculate that one... help me out please

## All 2 Replies

That's one of those code passages you can find on the web.

Both look like viable code solutions.

Here is one solution for your problem that i found.

``````#include <stdio.h>
#include <time.h>

/* checks whether the given input is leap year feb or not */
int leapYearFeb(int year, int mon) {
int flag = 0;
if (year % 100 == 0) {
if (year % 400 == 0) {
if (mon == 2) {
flag = 1;
}
}
} else if (year % 4 == 0) {
if (mon == 2) {
flag = 1;
}
}
return (flag);
}

int main() {
/* days in months */
int daysInMon[] = {31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31};
int days, month, year;
char dob[100];
time_t ts;
struct tm *ct;

/* get the date of birth from the user */
fgets(dob, 100, stdin);
sscanf(dob, "%d/%d/%d", &days, &month, &year);
ts = time(NULL);
ct = localtime(&ts);
/* scan the year, month and year from the input string */
printf("Current Date: %d/%d/%d\n",
ct->tm_mday, ct->tm_mon + 1, ct->tm_year + 1900);

days = daysInMon[month - 1] - days + 1;

/* checking whether month is leap year feb - 29 days*/
if (leapYearFeb(year, month)) {
days = days + 1;
}

/* calculating the no of days, years and months */
days = days + ct->tm_mday;
month = (12 - month) + (ct->tm_mon);
year = (ct->tm_year + 1900) - year - 1;

/* checking for leap year feb - 29 days */
if (leapYearFeb((ct->tm_year + 1900), (ct->tm_mon + 1))) {
if (days >= (daysInMon[ct->tm_mon] + 1)) {
days = days - (daysInMon[ct->tm_mon] + 1);
month = month + 1;
}
} else if (days >= daysInMon[ct->tm_mon]) {
days = days - (daysInMon[ct->tm_mon]);
month = month + 1;
}

if (month >= 12) {
year = year + 1;
month = month - 12;
}

/* print the result */
printf("Age: %d year %d months and %d days\n", year, month, days);
return 0;
}
``````

From Here i got the answer.

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