Guys i cant imagine about how i'm gonna calculate that one... help me out please
rproffitt 1,425
That's one of those code passages you can find on the web.
So here's my first 2 search links.
https://www.google.com/search?q=How+to+calculate+someone's+age%2C+in+days%2C+months+and+years+in+c
https://www.google.com/search?q=How+to+calculate+someone's+age%2C+in+days%2C+months+and+years+in+pascal
Both look like viable code solutions.
Here is one solution for your problem that i found.
#include <stdio.h>
#include <time.h>
/* checks whether the given input is leap year feb or not */
int leapYearFeb(int year, int mon) {
int flag = 0;
if (year % 100 == 0) {
if (year % 400 == 0) {
if (mon == 2) {
flag = 1;
}
}
} else if (year % 4 == 0) {
if (mon == 2) {
flag = 1;
}
}
return (flag);
}
int main() {
/* days in months */
int daysInMon[] = {31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31};
int days, month, year;
char dob[100];
time_t ts;
struct tm *ct;
/* get the date of birth from the user */
printf("Enter your days of birth:");
fgets(dob, 100, stdin);
sscanf(dob, "%d/%d/%d", &days, &month, &year);
ts = time(NULL);
ct = localtime(&ts);
/* scan the year, month and year from the input string */
printf("Current Date: %d/%d/%d\n",
ct->tm_mday, ct->tm_mon + 1, ct->tm_year + 1900);
days = daysInMon[month - 1] - days + 1;
/* checking whether month is leap year feb - 29 days*/
if (leapYearFeb(year, month)) {
days = days + 1;
}
/* calculating the no of days, years and months */
days = days + ct->tm_mday;
month = (12 - month) + (ct->tm_mon);
year = (ct->tm_year + 1900) - year - 1;
/* checking for leap year feb - 29 days */
if (leapYearFeb((ct->tm_year + 1900), (ct->tm_mon + 1))) {
if (days >= (daysInMon[ct->tm_mon] + 1)) {
days = days - (daysInMon[ct->tm_mon] + 1);
month = month + 1;
}
} else if (days >= daysInMon[ct->tm_mon]) {
days = days - (daysInMon[ct->tm_mon]);
month = month + 1;
}
if (month >= 12) {
year = year + 1;
month = month - 12;
}
/* print the result */
printf("Age: %d year %d months and %d days\n", year, month, days);
return 0;
}
From Here i got the answer.