``````AVGTIL0 – Write a program to accept integers from the keyboard until a zero is entered. Print the sum and average of the even numbers. Ignore any odd numbers in your calculations and print an appropriate message. I am working on this program more than two days.

#include "stdafx.h"
#include <iostream>
#include <iomanip>
#include <string>
#include <fstream>
#include <stdio.h>

using namespace std;

void Pause()
{
string junk;
cout << "Press any to continue ... ";
cin.ignore();
getline(cin, junk);
}

int main()
{
// declare file variables
// int x, evenNumber, averageEven;
int entNum, ans;
int even, x;
int odd;

// get input
cout  << "What is the integer of X: ";
cin >> x;
cout << endl;

//display results

do
{
even=0;
odd=0;
scanf("%d",& entNum);
ans = entNum%2;

if(ans==0)
{
even++;
}
else if(ans!=0)
{
odd++;
}
}
while(entNum!=0);

// if (x %2==0)

// else if ( x==0)
// averageEven = evenNumber
cout <<" average of the even numbers is: "<< even << endl;

// freeze screen
Pause();
return (0);
}``````

## All 5 Replies

When I run the program give me the same result whatever I change on it. I need help
Thanks,

Here is a simple solution that I came up with. Let me know if that helps or if you have any questions about it.

``````#include <iostream>

using namespace std;

bool isOdd(int input);

int main()
{
int input;
int sum = 0;
int count = 0;

do
{
cout << "Enter a number: ";
cin >> input;

if(isOdd(input) == true && input != 0)
{
sum = sum + input;
count++;
}

}while(input != 0)

cout << "The total is: " << sum << endl;
cout << "The average is: " << sum / count << endl;

return 0;

}

bool isOdd(int input)
{
if(input % 2== 0)
{
return true;
}
else
return false;
}``````

You also needed to consider that 0 is also an even number, which is why I added the statement "&& input != 0)"

that isOdd function checks if the boolean is even. Change the 2 to a 1

and below sum = sum + input; put odd++;

and change sum to oddSum and count to oddCount

and add an else if (inOdd(input) == false && input != 0 to the if statement with the same code as the first part of the if statement except evenSum and evenCount

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