I tried to do codes to get e^x by using maclaurin series but it gives 0 .

[Kepler123]

#include <stdio.h>
#include <math.h>

int main()

    float i, x;
    double fact=0, sum=0;

    printf("Enter value of x as the power of e: ");
    scanf("%f", &x);

    printf("Enter n as the number of terms:  ");
    scanf("%d",&i);    

    for (i = 0; i < 99999; i++)

    {   
        sum = 1 + x;
        fact = fact * i;
        sum = sum + pow(x, i)/(fact);   
    }
    if (sum == sum)

    printf("The value of e^%f is %lf",x,sum);

    return 0;

[Reverend Jim]

Why are you asking for n then reading it into i? And why are you then just ignoring it in your loop control?

[xrjf]

Here is the series solution and an alternative solution. In you can opt for any of both, solution #2 is more accurate, more concise and faster. I hope you can understand and tranlate the VB.Net code:

        Dim sum As Double = 0
        Dim fact As BigInteger = 1
        Dim esx As String = InputBox("x = ?")
        Dim x As Double = Double.Parse(esx)
        Dim x0 As Double = x
        Dim es As String = InputBox("n = ?")
        Dim n As Int32 = Int32.Parse(es)
        es = InputBox("solution 1/2")
        If es = "1" Then
            ' Solution #1 '
            sum = 1 + x
            For i As Int32 = 1 To n
                x *= x
                fact *= i + 1
                sum += x / CType(fact, Double)
            Next
        Else
            ' Solution #2 '
            ' exp(x) = lim(1+x/n)^n when n->Infinity  '
            sum = Math.Pow(1 + x / n, n)
        End If
        TextBox1.Text = sum.ToString + " " + Math.Exp(x0).ToString