0

Hello all.

I try to learn some Ajax, but find it some difficult. The task I'm trying to do, is to use Ajax to register a new user for my application.

The problem is that the request don't seem to pass the POST-variables to the php-script on the server side, and I can't just see what's wrong!

Please take look at the code below:

function createXMLHttpRequest() {
var request = false;

/* Does this browser support the XMLHttpRequest object? */
if (window.XMLHttpRequest) {
if (typeof XMLHttpRequest != 'undefined') {
/* Try to create a new XMLHttpRequest object */
try {
request = new XMLHttpRequest();
} catch (e) {
alert('Could not create XMLHttpRequest');
request = false;
}
/* Does this browser support ActiveX objects? */
} else if (window.ActiveXObject) {
/* Try to create a new ActiveX XMLHTTP object */
try {
request = new ActiveXObject('Msxml2.XMLHTTP');
} catch (e) {
alert('Could not create XMLHttpRequest');
return false;
}
}
}
return request;
}

function checkRegistering() {
var request = createXMLHttpRequest();
var name = $F('name');
var email = $F('email');
var username = $F('username');
var password = $F('password');
var params = 'name=' + name + '&email=' + email + '&username=' + username + '&password=' + password;

if(request) {
url = 'checkregister.php?' + params;
request.onreadystatechange = parseResponse(request);
request.open('POST', url, true);
request.send(null);
}
}

function parseResponse(request) {
alert('onreadystatechange');
alert('request.responseText=' + request.responseText);
if(request.readyState == 4) {
if(request.status == 200) {
var response = request.responseText;
} else {
alert('There was a problem retrieving the data: \n' + request.statusText);
}
request = null;
}
}

The serverside-script is just:

<?php
require_once 'db.php';

$xml = <<< PROLOG
<?xml version="1.0" encoding="iso-8859-1"?>
PROLOG;

$db = new db;

$userdata = array("name" => $_POST['name'],
"email" => $_POST['email'],
"username" => $_POST['username'],
"password" => $_POST['password']);

print_r($userdata);

?>

Very simple (should be).

The problem is that the posted variables don't arrive to the script - and therefor no usable return either.

Whats wrong?

2
Contributors
1
Reply
2
Views
7 Years
Discussion Span
Last Post by Thirusha
0

I dont know PHP, but what u can do is alert the variables before u put them inside the url variable.

Also i think your ajax code is incorrect, this

request.onreadystatechange = parseResponse(request);

should be:

request.onreadystatechange = parseResponse;

You dont need to send the request variable to that function. also the function parseResponse would then not accept a variable.

This question has already been answered. Start a new discussion instead.
Have something to contribute to this discussion? Please be thoughtful, detailed and courteous, and be sure to adhere to our posting rules.