how to get the filename and size

Question

niths -1 Posting Whiz in Training

14 Years Ago

hi,
i am new to php. i want to get the uploaded filename,uploadedby,date, and size of the file. dont know how to get the name of the file and size. so please any one....

<html>
<body>
<form enctype="multipart/form-data" action="upload2.php" method="POST">
<table>
<tr>
<td><img src="Logofinalcopy.gif"></td>
</tr>
</table>
<table>
<br><br>
<tr>
	<td>
		<strong>Please choose a file: </strong>
	</td> 
	<td>
		<input name="uploaded" type="file"><br>
    </td>
</tr>
<tr><td>
<input type="submit" value="upload"></td></tr>

</table></form></body></html>
<?php
ob_start();
@session_start();
require_once ("check.php");
$con=mysql_connect("10.70.1.50","invensis","invensis");
if(!$con)
    {
             die('Could not connect: ' . mysql_error());
    }
mysql_select_db("database_myproject",$con);


?>
<html>
<body>
<table border="1" cellspacing="0" cellpadding="0" align="center" style="width: 500px">
<tr>
<th>filename</th>
<th>uploadedby</th>
<th>uploadeddate</th>
<th>size</th></tr>


<tr>
<td><?php ?></td>
<td><?php echo $username; ?></td>
<td><?php echo date("Y-m-d");?></td>
<td><?php ?> </td></tr>
<?php
  
?>
</table></body></html>

php

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31 Replies
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10 Hours Discussion Span
Latest Post 14 Years Ago Latest Post by prem2

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prem2 -2 Posting Whiz in Training · Answer 1 · 2010-04-05T12:12:55+00:00

Hi,
In upload2.php file using the following line.
print_r($_FILES);

you can see the name of the file,size,type etc.

Thank you,
Prem

niths -1 Posting Whiz in Training · Answer 2 · 2010-04-05T12:23:10+00:00

actually i need to display the filename , uploadedby,uploaded date, and size of the file which is uploaded in a table. so please check this once again..

prem2 -2 Posting Whiz in Training · Answer 3 · 2010-04-05T12:36:00+00:00

hi,
check whether what output your are getting.In your code you does not mentioned in which location your file is uploaded.

Thank you,

niths -1 Posting Whiz in Training · Answer 4 · 2010-04-05T12:41:11+00:00

actually i need to display the filename , uploadedby,uploaded date, and size of the file which is uploaded in a table. so please check this once again..

iam getting Array() in the filename column.
ok i am sending upload2.php code also...

<?php
 $dirname=$_POST['projectname'];
 $dir="files";

    if(is_dir($dirname))
    {
        $target = "$dir/$dirname/";
        $target = $target . basename( $_FILES['uploaded']['name']) ; 
        $ok=1; 
        if ($ok==0) 
        { 
            Echo "Sorry your file was not uploaded"; 
        } 
        else 
        { 
            if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) 
            { 
                echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; 
                echo '<a href="login_success.php">Back</a>';
            } 
            else 
            { 
                echo " "; 
            } 
        }
     }
     else
     {
        $path="$dir//$dirname";
        @mkdir($path,0777,true);
        $target = "$dir/$dirname/";
        $target = $target . basename( $_FILES['uploaded']['name']); 
        $ok=1; 
        if ($ok==0) 
        { 
            echo "Sorry your file was not uploaded"; 
        } 
        else 
        { 
            if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) 
            { 
                echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; 
                
            } 
            else 
            { 
                echo " "; 
            } 
        }
     }
    
 
?>

prem2 -2 Posting Whiz in Training · Answer 5 · 2010-04-05T12:44:37+00:00

prem2 -2 Posting Whiz in Training

14 Years Ago

Is your file is uploaded in the following destination.

Edited 14 Years Ago by prem2 because: n/a

niths -1 Posting Whiz in Training · Answer 6 · 2010-04-05T12:48:44+00:00

Is your file is uploaded in the following destination.

yes. i can see the uploaded files in files folder. should we need to create sessions for this...

prem2 -2 Posting Whiz in Training · Answer 7 · 2010-04-05T12:59:09+00:00

In upload2.php when you use the below line you can see the file name.

echo "File name " . $_FILES["file"]["name"] . "<br />";

If you want to display the file name in table. you must assign the file name in variable and pass it into the url.

niths -1 Posting Whiz in Training · Answer 8 · 2010-04-05T13:06:44+00:00

In upload2.php when you use the below line you can see the file name.

echo "File name " . $_FILES["file"]["name"] . "<br />";

If you want to display the file name in table. you must assign the file name in variable and pass it into the url.

can u give me clear explanation, how to display filename in table.

prem2 -2 Posting Whiz in Training · Answer 9 · 2010-04-05T13:22:10+00:00

you must use java script to pass the values using the hidden attribute.That is the simplest way.

You can try this code but it is not efficient one.
Remove the follwing line in your code.
echo '<a href="login_success.php">Back</a>';
Use this:
$filename=$_FILES;
header("Location:login_success.php?i=$filename);

In display file use the code:
<?php $filename=$_REQUEST?>
<td><?php $filename ?></td>
<td><?php echo $username; ?></td>
<td><?php echo date("Y-m-d");?></td>

prem2 -2 Posting Whiz in Training · Answer 10 · 2010-04-05T13:44:50+00:00

change the following line.
<a href="login_success.php">Back</a>

Try this may be it will also help you.
$filename=$_FILES;
<a href="login_success.php?i=$filename">Back</a>

niths -1 Posting Whiz in Training · Answer 11 · 2010-04-05T13:54:23+00:00

change the following line.
<a href="login_success.php">Back</a>
Try this may be it will also help you.
$filename=$_FILES;
<a href="login_success.php?i=$filename">Back</a>

no i am not getting any filename. ok i removed completly this line
<a href="login_success.php">Back</a>. assume that it is not their.

prem2 -2 Posting Whiz in Training · Answer 12 · 2010-04-05T14:30:23+00:00

You can also try this code.
$filename=$_FILES;
<a href="login_success.php?i=$filename">Back</a>';

prem2 -2 Posting Whiz in Training · Answer 13 · 2010-04-05T14:32:40+00:00

Check whether the file name you get.
echo $filename=$_FILES;

prem2 -2 Posting Whiz in Training · Answer 14 · 2010-04-05T15:02:13+00:00

check whether you are getting the file name;
$filename=$_FILES;
echo $filename;

niths -1 Posting Whiz in Training · Answer 15 · 2010-04-05T15:09:25+00:00

check whether you are getting the file name;
$filename=$_FILES;
echo $filename;

It is not printing filename. iam in a confusion wer to keep that.

prem2 -2 Posting Whiz in Training · Answer 16 · 2010-04-05T15:15:27+00:00

Inside the if block;

if(move_uploaded_file($_FILES, $target))
{
echo "The file ". basename( $_FILES). " has been uploaded";
$filename=$_FILES;
echo $filename;
print_r($_FILES);
echo '<a href="login_success.php">Back</a>';

}

niths -1 Posting Whiz in Training · Answer 17 · 2010-04-05T15:20:24+00:00

Inside the if block;
if(move_uploaded_file($_FILES, $target))
{
echo "The file ". basename( $_FILES). " has been uploaded";
$filename=$_FILES;
echo $filename;
print_r($_FILES);
echo '<a href="login_success.php">Back</a>';
}

i am getting the following on the browser
The file has been uploadedArray ( [uploaded] => Array ( [name] => view.php [type] => text/plain [tmp_name] => C:\WINDOWS\temp\php72.tmp [error] => 0 => 1654 ) )

prem2 -2 Posting Whiz in Training · Answer 18 · 2010-04-05T15:38:25+00:00

Sorry i mistakenly typed uploadedfile..change this line.

$filename=$_FILES;
echo $filename;

niths -1 Posting Whiz in Training · Answer 19 · 2010-04-05T15:41:46+00:00

Sorry i mistakenly typed uploadedfile..change this line.
$filename=$_FILES;
echo $filename;

The file has been uploadedArray ( [uploaded] => Array ( [name] => view.php [type] => text/html [tmp_name] => C:\Documents and Settings\Administrator\Local Settings\temp\php86.tmp [error] => 0 => 1654 ) )

prem2 -2 Posting Whiz in Training · Answer 20 · 2010-04-05T15:51:41+00:00

you must get the filename;Then only you can able to pass it to another page.

$filename=$_FILES;
echo "********".$filename;

try and check once again...

niths -1 Posting Whiz in Training · Answer 21 · 2010-04-05T15:59:02+00:00

you must get the filename;Then only you can able to pass it to another page.

$filename=$_FILES;
echo "********".$filename;
try and check once again...

yes i am getting the uploaded filename as empdetails and also size.
The file has been uploaded********empdetails.phpArray ( [uploaded] => Array ( [name] => empdetails.php [type] => text/plain [tmp_name] => C:\WINDOWS\temp\php8F.tmp [error] => 0 => 5048 ) )

prem2 -2 Posting Whiz in Training · Answer 22 · 2010-04-05T16:02:55+00:00

try this line..
<a href="login_success.php?i=$filename">Back</a>

niths -1 Posting Whiz in Training · Answer 23 · 2010-04-05T16:06:19+00:00

try this line..
<a href="login_success.php?i=$filename">Back</a>

actually this line is not there. i mistakenly type it.
<a href="login_success.php?i=$filename">Back</a>

niths -1 Posting Whiz in Training · Answer 24 · 2010-04-05T16:09:46+00:00

try this line..
<a href="login_success.php?i=$filename">Back</a>

wat the thing is i need to place that filename and size in the table. so please help me for that...

prem2 -2 Posting Whiz in Training · Answer 25 · 2010-04-05T16:10:16+00:00

put the line

<a href="login_success.php?i=$filename">Back</a>

In table display use the code:

<?php $filename=$_REQUEST[i]?>
<td><?php $filename ?></td>
<td><?php echo $username; ?></td>
<td><?php echo date("Y-m-d");?></td>

niths -1 Posting Whiz in Training · Answer 26 · 2010-04-05T16:20:08+00:00

put the line
<a href="login_success.php?i=$filename">Back</a>
In table display use the code:
<?php $filename=$_REQUEST?>
<td><?php $filename ?></td>
<td><?php echo $username; ?></td>
<td><?php echo date("Y-m-d");?></td>

this line is not present. i am sorry for that.
<a href="login_success.php?i=$filename">Back</a>
i had kept this line
<?php $filename=$_REQUEST?>
but i didnt get it.

prem2 -2 Posting Whiz in Training · Answer 27 · 2010-04-05T16:25:26+00:00

Remove the follwing line in your code. header("Location:login_success.php?i=$filename); put the line <a href="login_success.php?i=$filename">Back</a> when you click the back.It will go to login_success.php

In table design you include the code mentioned below

<?php print_r($_REQUEST); ?>
<?php $filename=$_REQUEST[i]?>
<td><?php echo $filename ?></td>
<td><?php echo $username; ?></td>
<td><?php echo date("Y-m-d");?></td>

niths -1 Posting Whiz in Training · Answer 28 · 2010-04-05T16:28:10+00:00

Remove the follwing line in your code.
header("Location:login_success.php?i=$filename);
put the line
<a href="login_success.php?i=$filename">Back</a>

when you click the back.It will go to login_success.php
In table design you include the code mentioned below
<?php print_r($_REQUEST); ?>
<?php $filename=$_REQUEST?>
<td><?php echo $filename ?></td>
<td><?php echo $username; ?></td>
<td><?php echo date("Y-m-d");?></td>

but i am not having any login_success.php page. i mistakenly typed it.

prem2 -2 Posting Whiz in Training · Answer 29 · 2010-04-05T16:37:18+00:00

if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target))
{
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded";
echo '<a href="login_success.php">Back</a>';
}

In the above code you have mentioned it.Then when u click the back button where it will go..In which page you want to display the table.
You want to display the table in same upload2.php file?