I have a form working perfectly, however I need to put this form in a $display_block .= "... ... ...";
which I have done and which works fine also (minus the following radio code).
My problem is that when I add this code back inside the display block, it causes an error (my guess is bad syntax ...<?php if ...)
The error is Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in ... on line ... (<input type='radio')
$display_block .= " ... <div...> <input type='radio' name='status' value='Visible' <?php if ($_POST['status']=='Visible' || !isset($_POST['status'])) echo 'checked';?>>Visible <input type='radio' name='status' value='Hidden' <?php if ($_POST['status']=='Hidden') echo 'checked';?>>Hidden </div> ... ";
I have tried to break it up with ". ." etc, but I just have not figured it yet.
Thanks in advance if someone finds a fix before I do.