Member Avatar for killbill07

I have a folder with pics and I need to use scandir() to show all images in a html file. But scandir returns, for example, "image.jpg1". Why? How can I do that withouth problems?

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  • Latest Post Latest Post by monica singh

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Member Avatar for hielo

Try:

$f=scandir('/Images/');
foreach($f as $p)
{
 echo '<img src="/Images/'.$p.'" />';
}
Member Avatar for richieking

try the improve of hielo.

$f=scandir('/Images/');
foreach($f as $p)
{
  if($p=="." || $p=="."){
}
else{
 echo '<img src="/Images/'.$p.'" />';
}}
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