It's only displaying the first result and not the others. What am I doing wrong?
I'm selecting the items the user occupies.
Then I'm selecting the name and image of that item from the item table.

echo "<table cellspacing=\"0\" class=\"news\" align=\"center\">";
	echo "<tr>";
	$sql = "SELECT * FROM useritems WHERE userid='".$_SESSION['userid']."' LIMIT $offset, $rowsperpage"; //selects all the users items to whoever is logged in
	$result = mysqli_query($cxn,$sql) or die(mysqli_erro($cxn));
	$imagecount = 0;
	while ($row = mysqli_fetch_assoc($result)) //while there are still results
		$quantity = $row['quantity'];
		$itemid = $row['itemid'];
		$sql = "SELECT * FROM items WHERE itemid='".$itemid."'"; //selecting the name and image of the item that is displaying
		$result = mysqli_query($cxn, $sql) or die(mysqli_error($cxn));
		$row = mysqli_fetch_assoc($result);
		$name = $row['name'];
		$image = $row['image'];
		if ($imagecount%5 == 0) //after 5 items have been listed, start a new line
			echo "</tr>";
			echo "<tr>";
	echo "<td width=\"120px\" align=\"center\">";
	echo "<img src=\"http://www.elvonica.com/".$image."\"><br>";
	echo $name." (".$quantity.")";
	echo "</td>";
	$imagecount++; //after one item has been displayed, redo the loop if there are still results
	echo "</table>";
6 Years
Discussion Span
Last Post by C#Jaap

You calling twice

$row = mysqli_fetch_assoc($result);

With the second query you affect the $result, $sql and $row of the first query, I guess.

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